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3 years ago

3 m/s north is an example of a(n) ____.

2 answers:

6 0

It is velocity. Velocity is a vector quantity. Vector quantity has both magnitude and direction. 3 m/s north has 3 m/s as magnitude and north as direction.

alexandr1967 [171]3 years ago

4 0

Rate of speed (3 m/s north is three miles per second north, so it's a rate of speed)

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An airplane during departure has a constant acceleration of 3 m / s².

Rama09 [41]

Constant acceleration of plane = 3m/s²

a) Speed of the plane after 4s

Acceleration = speed/time

3m/s² = speed/4s

S = 12m/s

The speed of the plane after 4s is 12m/s.

b) Flight point will be termed as the point the plane got initial speed, u, 20m/s

Find speed after 8s, v

a = 3m/s²

from,

a = v - u

3 = v - 20

24 = v - 20

v = 44m/s

After 8s the plane would've 44m/s speed.

6 0

2 years ago

Assume the following values: d1 = 0.880 m , d2 = 1.11 m , d3 = 0.560 m , d4 = 2.08 m , F1 = 510 N , F2 = 306 N , F3 = 501 N , F4

dsp73

Answer:

= 2630.6 N.m

Explanation:

(FR)x = ΣFx = -F4 = -407 N

(FR)y = ΣFy =-F1-F2 -F3 = -510 - 306 - 501 = -1317 N

(MR)B =ΣM + Σ(±Fd)

= MA + F1(d1 +d2) + F2d2 - F4d3

= 1504 + 510(0.880+1.11) +306(1.11) - 407(0.560)

= 2630.64 N.m (counterclockwise)

6 0

3 years ago

What type of stress can cause an anticline? A. Compression B. force C. shear

Andrei [34K]

The stress that can cause on the anticline , is the Compression

4 0

2 years ago

Read 2 more answers

A homeowner uses a snowblower to clear his driveway. knowing that the snow is discharged at an average angle of 40° with the hor

Nesterboy [21]

given that snow is projected at an angle of 40 degree

It range is given as a = 19 ft

$a = 19 * 0.3048 = 5.8 m$

now we can use the formula of horizontal range

$R = \frac{v_o^2 sin2\theta}{g}$

$5.8 =\frac{ v_o^2 sin(2*40)}{9.8}$

$5.8 = \frac{v_o^2 * sin80}{9.8}$

$v_o^2 = 57.7$

$v_o = 7.6 m/s$

so its initial speed must be 7.6 m/s

8 0

3 years ago

A driver in a 2000 kg Porsche wishes to pass to pass a slow-moving school bus on a four-lane road. What is the average power in

Kryger [21]

The average power is $3.0\cdot 10^6 W$

Explanation:

First of all, we calculate the work done to accelerate the car; according to the work-energy theorem, the work done is equal to the change in kinetic energy of the car:

$W=K_f -K_i= \frac{1}{2}mv^2-\frac{1}{2}mu^2$