Answer:
B. 17,705.1 J
Explanation:
The hear released when the mercury condenses into a liquid is given by:

where
m = 0.06 kg is the mass of the mercury
is the latent heat of vaporization
For mercury, the latent heat of vaporization is
, so the heat released during the process is:

So, the closest option is
B. 17,705.1 J
Answer:
v_squid = - 2,286 m / s
Explanation:
This exercise can be solved using conservation of the moment, the system is made up of the squid plus the water inside, therefore the force to expel the water is an internal force and the moment is conserved.
Initial moment. Before expelling the water
p₀ = 0
the squid is at rest
Final moment. After expelling the water
= M V_squid + m v_water
p₀ = p_{f}
0 = M V_squid + m v_water
c_squid = -m v_water / M
The mass of the squid without water is
M = 9 -2 = 7 kg
let's calculate
v_squid = 2 8/7
v_squid = - 2,286 m / s
The negative sign indicates that the squid is moving in the opposite direction of the water
Answer:
10.3 cm³
Explanation:
From the question given above, the following data were obtained:
Original volume (V₁) = 10 cm³
Initial temperature (θ₁) = 20 °C
Final temperature (θ₂) = 50 °C
Cubic expansivity (γ) = 10¯³ K¯¹
Final volume (V₂) =?
γ = V₂ – V₁ / V₁(θ₂ – θ₁)
10¯³ = V₂ – 10 / 10( 50 – 20)
10¯³ = V₂ – 10 / 10(30)
10¯³ = V₂ – 10 / 300
Cross multiply
10¯³ × 300 = V₂ – 10
0.3 = V₂ – 10
Collect like terms
0.3 + 10 = V₂
10.3 = V₂
V₂ = 10.3 cm³
Thus, the volume at 50 °C is 10.3 cm³
Answer:
30
Explanation:
Assuming the velocity is 3π radians <em>per second</em>, the top will spin through an angle of ...
(3π radians/s)(20 s) = 60π radians
Since each revolution is 2π radians, that is ...
(60π radians)/(2π radians/revolution) = 30 revolutions
Answer:
we would have no oxygen and barely any water.