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TiliK225 [7]
2 years ago
5

Xy=1 for x=2, dx/dt= -2 find dy/dt

Mathematics
1 answer:
dexar [7]2 years ago
7 0
\bf xy=1\iff y = \cfrac{1}{x}\iff y = x^{-1}\\\\
-----------------------------\\\\
\cfrac{dy}{dt}=-x^{-2}\cdot \cfrac{dx}{dt}\impliedby \textit{using the chain-rule}
\\\\\\
\left. \cfrac{dy}{dt}=-\cfrac{\frac{dx}{dt}}{x^2} \right|{
\begin{array}{llll}
x=2\\
\frac{dx}{dt}=-2
\end{array}}\implies \cfrac{dy}{dt}=-\cfrac{-2}{2^2}
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In a circle of radius 10 cm, a sector has an area of 40 (pi) sq. cm. What is the degree measure of the arc of the sector?
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Answer:

144°

Step-by-step explanation:

First, find the area of the circle, with the formula A = \pir²

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Using this, create a proportion that relates the area of the sector to the degree measure of the arc.

Let x represent the degree measure of the arc of the sector:

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StartLayout enlarged left-brace 1st row 4 x minus 5 y = 5 2nd row negative 0.08 x + 0.10 y = 0.10 EndLayout
FinnZ [79.3K]

Answer:

x = 1.25

y = 0

Step-by-step explanation:

Given

4x - 5y = 5

0.08x + 0.10y = 0.10

Required

Determine the solution

Make x the subject of formula in: 4x - 5y = 5

4x  = 5 + 5y

Divide both sides by 4

\frac{4x}{4}  = \frac{5 + 5y}{4}

x = \frac{5 + 5y}{4}

Substitute x = \frac{5 + 5y}{4} in 0.08x + 0.10y = 0.10

0.08(\frac{5 + 5y}{4}) + 0.10y = 0.10

Solve the fraction

0.02(5 + 5y) + 0.10y = 0.10

Open the bracket

0.1 + 0.1y + 0.10y = 0.10

0.1 + 0.2y = 0.10

Subtract 0.1 from both sides

0.1-0.1 + 0.2y = 0.10 - 0.1

0.2y = 0

Divide both sides by 0.2

y =0

Substitute 0 for y in x = \frac{5 + 5y}{4}

x = \frac{5 + 5*0}{4}

x = \frac{5 + 0}{4}

x = \frac{5 }{4}

x = 1.25

5 0
3 years ago
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