Let's find out how much she spent every month.
4000 (starting money) - 2800 (remaining money) = 1200 spent over 3 months
1200/3 = 400 per month was spent
So if she continues to spend 400 a month?
How many months are left? 12 (months of the year) - 3 (months she already spent) = 9
So 9 (remaining months) * 400 (amt per month) = 3600 she'll spend at the going rate over 9 months.
But she only has 2800 left.
2800 (remaining) - 3600 (estimated total of spending) = -800
So she will be 800$ in debt at the end of the year at the current rate.
Answer:4200-600m=1800
Step-by-step explanation:
4200-600m=1800
Subtract 4200 from 1800
-600m=-3600
Divide both sides by -600
m=6
9514 1404 393
Answer:
22/44
Step-by-step explanation:
The probability of black is the ratio of black cards to all cards. If the Ace and 2 are removed from each suit, there will be 11 of the 13 cards remaining. 2 suits are black, for a total of 2×11 = 22 black cards. Of course there are 4 suits altogether, for a total of 4×11 = 44 total cards. Then you have ...
P(black) = (black cards)/(total cards)
P(black) = 22/44
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You are expected to be familiar with the fact that a deck of 52 playing cards consists of 4 suits: diamonds, clubs, hearts, spades. Each suit has 13 cards, identified as Ace, 2, 3, ..., 10, Jack, Queen, King. The clubs and spades are black; the diamonds and hearts are red.
Answer:
A
Step-by-step explanation:
angle A is 90 and c and b have to be equal
Part a)
MAD = median of absolute deviations
MAD = median of the set formed by : |each value - Median|
Then, first you have to find the median of the original set
The original set is (<span>38, 43, 45, 50, 51, 56, 67)
The median is the value of the middle (when the set is sorte). This is 50.
Now calculate the absolute deviation of each data from the median of the data.
1) |38 - 50| = 12
2) |43 - 50| = 7
3) |45 - 50| = 5
4) |50 - 50| = 0
5) |51 - 50| = 1
6) |56 - 50| = 6
7) |67 - 50| = 17
Now arrange the asolute deviations in order
(0, 1, 5, 6, 7, 12, 17)
The median is the value of the middle: 6.
Then the MAD is 6.
Part b) MAD represents the median of the of the absolute deviations from the median of the data.
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