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lorasvet [3.4K]
3 years ago
15

Which equations below represent lines that are perpendicular to the line that contains (1, -2) and (3, 4)? (CHECK PICS FOR ANSWE

R CHOICES, CHOOSE MORE THAN ONE IF NECESSARY)

Mathematics
1 answer:
Gala2k [10]3 years ago
8 0

First, let's find the slope of the line from the points given.

m = (4 - - 2) / (3 - 1)

m = 6 / 2

m = 3

Secondly, we know that a line perpendicular to the original must have a slope that is the opposite reciprocal of the original. For the given points, the opposite reciprocal slope would be -1/3.

Now, we can put all of the equations below into slope intercept form and find the ones that have a slope of -1/3.

Equation 1: Correct

y = -1/3x - 5

Equation 2: Incorrect

y = 3x - 3

Equation 3: Incorrect

y - 2 = 3(x + 1)

y - 2 = 3x + 1

y = 3x + 2

Equation 4: Correct

x + 3y = 9

3y = -x + 9

y = -1/3x + 3

Equation 5: Incorrect

3x + y = -5

y = -3x - 5

Hope this helps!! :)

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Solve for x then find the measure of angle B
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Answer:

5

Step-by-step explanation:

thanks for the points

4 0
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20. A rectangle has an area of 45 cm². The length is one cm less than twice the width. Find the dimensions of
prohojiy [21]
Width = 5, length = 9

Area = length * width

length = (2 * width) - 1

sub equation for length

45 = (2w - 1) * w
45 = 2w^2 - w
2w^2 - w - 45 = 0
(2w - 9)(w - 5)
2w - 9 = 0
w = 9/2, l = 8 no

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7 0
3 years ago
Find the slope of the line graphed below .
icang [17]

Answer:

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4 0
3 years ago
NO LINKS??
yulyashka [42]

Answer:

(a) The maximum height of the ball is 16 feet at 1 seconds.

(b) The ball hits the ground at 2 seconds.

PART (A) :

Given function: h(t) = -16t² + 32t

Comparing to quadratic function: ax² + bx + c

In this function: a = -16, b = 32, c = 0

<u>To find the maximum height</u>, use the vertex formula:

\sf x = \dfrac{-b}{2a}

<u>Insert values</u>

\rightarrow \sf t = \dfrac{-32}{2(-16)} = 1

Then find h(t) = -16(1)² + 32(1) = 16 feet

Conclusion: The maximum height of the ball is 16 feet at 1 seconds.

PART (B) :

When the ball hits the ground, the height [h(t)] will be 0 ft

-16t² + 32t = 0

-16t(t - 2) = 0

-16t = 0, t - 2 = 0

t = 0, t = 2

The ball hits the ground at 2 seconds. Note: the other 0 seconds is for when the ball was launched at the beginning.

8 0
2 years ago
Read 2 more answers
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