Your answer is "<span>surface of a sphere"
Hope this helps.</span>
The number converted is ![0.0467 \frac{(kg)(s)}{m^3}](https://tex.z-dn.net/?f=0.0467%20%5Cfrac%7B%28kg%29%28s%29%7D%7Bm%5E3%7D)
Explanation:
In order to convert from the original units to the final units, we have to keep in mind the following conversion factors:
![1 kg = 1000 g = 10^6 mg](https://tex.z-dn.net/?f=1%20kg%20%3D%201000%20g%20%3D%2010%5E6%20mg)
![1 min = 60 s](https://tex.z-dn.net/?f=1%20min%20%3D%2060%20s)
![1 m^3 = 1000 L](https://tex.z-dn.net/?f=1%20m%5E3%20%3D%201000%20L)
The original unit that we have is
![\frac{mg\cdot min}{L}](https://tex.z-dn.net/?f=%5Cfrac%7Bmg%5Ccdot%20min%7D%7BL%7D)
Therefore, it can be rewritten as:
![=\frac{mg \frac{1}{10^6 mg/kg}\cdot min\cdot 60 s/min}{L\frac{1}{1000L/m^3}}=0.06 \frac{(kg)(s)}{m^3}](https://tex.z-dn.net/?f=%3D%5Cfrac%7Bmg%20%5Cfrac%7B1%7D%7B10%5E6%20mg%2Fkg%7D%5Ccdot%20min%5Ccdot%20%2060%20s%2Fmin%7D%7BL%5Cfrac%7B1%7D%7B1000L%2Fm%5E3%7D%7D%3D0.06%20%5Cfrac%7B%28kg%29%28s%29%7D%7Bm%5E3%7D)
Therefore, since the initial number was 0.779, the final value is
![0.779\cdot 0.06 \frac{(kg)(s)}{m^3}=0.0467 \frac{(kg)(s)}{m^3}](https://tex.z-dn.net/?f=0.779%5Ccdot%200.06%20%5Cfrac%7B%28kg%29%28s%29%7D%7Bm%5E3%7D%3D0.0467%20%5Cfrac%7B%28kg%29%28s%29%7D%7Bm%5E3%7D)
#LearnwithBrainly
The FREQUENCY of light remains unchanged once it leaves the source.
Answer:
C. -0.6
Explanation:
Line is passing through the points ( - 3, 1) & (2, - 2)
Slope of line
![= \frac{ - 2 - 1}{2 - ( - 3)} = \frac{ - 3}{2 + 3} = \frac{ - 3}{5} = - 0.6 \\](https://tex.z-dn.net/?f=%20%3D%20%20%5Cfrac%7B%20-%202%20-%201%7D%7B2%20-%20%28%20-%203%29%7D%20%20%3D%20%20%5Cfrac%7B%20-%203%7D%7B2%20%2B%203%7D%20%20%3D%20%20%5Cfrac%7B%20-%203%7D%7B5%7D%20%20%3D%20%20-%200.6%20%5C%5C%20)
Answer:
A.) 1372 N
B.) 1316 N
C.) 1428 N
Explanation:
Given that a 140 kg load is attached to a crane, which moves the load vertically. Calculate the tension in the cable for the following cases:
a. The load moves downward at a constant velocity
At constant velocity, acceleration = 0
T - mg = ma
T - mg = 0
T = mg
T = 140 × 9.8
T = 1372N
b. The load accelerates downward at a rate 0.4 m/s??
Mg - T = ma
140 × 9.8 - T = 140 × 0.4
1372 - T = 56
-T = 56 - 1372
- T = - 1316
T = 1316N
C. The load accelerates upward at a rate 0.4 m/s??
T - mg = ma
T - 140 × 9.8 = 140 × 0.4
T - 1372 = 56
T = 56 + 1372
T = 1428N