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4 years ago

Gold-leaf electroscope uses

1 answer:

7 0

-identifies an electric charge
-it can identify its polarity (positive or negative) if you compare it to a charge that you already know
-can identify the magnitude of a charge (how big of a charge it is)

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A scuba diver has his lungs filled to half capacity (3 liters) when 10 m below the surface. If the diver holds his breath while

rjkz [21]

To solve this problem it is necessary to apply Boyle's law in which it is specified that

$P_1V_1 =P_2 V_2$

Where,

$P_1$ and $V_1$ are the initial pressure and volume values

$P_2$ and $V_2$ are the final pressure volume values

The final pressure here is the atmosphere, then

$P_2 = 101325 \approx 1*10^5Pa$

$h = 10m$

$\rho_w = 1000kg/m^3$

$V_1 = 3.0L$

Pressure at the water is given by,

$P_1 = P_2 -\rho gh$

$P_1 = 1*10^5 +1000*9.8*10 =198000Pa$

Using Boyle equation we have,

$V_2 = \frac{P_1V_1}{P_2}$

$V_2 = \frac{198000*3*10^5}{10^5}$

$V_2 = 5.9L$

Therefore the volume of the lungs at the surface is 5.9L

4 0

3 years ago

A cube of side 0.2 m rests on the floor as shown.

andrey2020 [161]

Pressure= hqg
H=depth
q=density
g=gravity

h=0.2
q=7
g=10

0.2*7*10= 14pa

FINAL ANSWER = 14pa

4 0

2 years ago

The next two questions refer to this situation: A rectangular loop with sides of length a= 1.00 cm and b= 2.70 cm is placed near

alisha [4.7K]

Answer:

a) $1.007 * 10^{-7}$ V.m , into the page

b) $-5.39 * 10^{-8}$ V, counterclockwise

Explanation:

a) $d\Phi = B.dA\\\\B_r = \frac{\mu_0I}{2\pi r}\\\\dA = b.dr\\\\\Phi = \int\limits^b_a {B.dA} = \int\limits^{a+d}_d {\frac{\mu_0I}{2\pi r}.b.dr} =\frac{\mu_0I}{2\pi }.b.ln(\frac{a+d}{d} )\\$

At t = 2.90, I = 3.62 + 1.49 * (2.90)^2 = 16.15 A

$\Phi = \frac{4\pi * 10^{-7}*16.15*0.027}{2\pi} ln(1.46/0.46) = 1.007 * 10^{-7}$ V.m

Direction is into the page.

b) $emf = -d\Phi/dt = -\frac{\mu_0}{2\pi }.b.ln(\frac{a+d}{d}).(2.98t)= \\=-\frac{4\pi * 10^{-7}*0.027}{2\pi} ln(1.46/0.46)*2.98*2.90= -5.39 * 10^{-8} V$

Direction is counterclockwise.

8 0

3 years ago

O lugar mais fundo do mar é a Trincheira de Mariana, localizada a 11 km de profundidade. Essa estrutura imensa está localizada n

ipn [44]

Sorry i dont speak spanish

3 0

4 years ago

What is the energy required to raise the temperature of 1 g of a substance by 1°c or 1 k?

lesya692 [45]

Answer:

Specific heat

Explanation:

The specific heat is the amount of heat, that is energy in transfer to or from a thermodynamic system, required to raise the temperature of 1 g of substance by one degree Celsius or one Kelvin, since one degree on the Celsius scale is equal to one Kelvin.

7 0

3 years ago