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4 years ago

How many 3-digit numbers exist, whose digits are distinct even numbers.

Mathematics

2 answers:

skad [1K]4 years ago

7 0

Answer:

328

Step-by-step explanation:

If z is 0, then x has 9 choices. Therefore, z and x can be chosen in (1 × 9) + (4 × 8) = 41 ways. For each of these ways, y can be chosen in 8 ways. Hence, the desired number is 41 × 8 = 328 numbers 3-digit even numbers exist with no repetitions.

Dahasolnce [82]4 years ago

5 0

Answer:

100

Step-by-step explanation:

my teacher told me and I got it right

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Solve for x. 5(х – 10) = 30 — 15х ox = 1 ox = 4 ox = 5 ох= 8 х = 8

Liula [17]

Answer:

x = 4

Step-by-step explanation:

Carry out the multiplication:

5(х – 10) = 30 — 15х => 5x - 50 = 30 - 15x

Combining the x terms, we get:

20x - 50 = 30

Combining the constants on the right side:

20x = 80

Dividing both sides by 20 yields x = 4 (second given answer)

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3 years ago

Is 13/18 greater than 15/24

maks197457 [2]

Answers:

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Step-by-step explanation:

13/18 gives 0.72222222 while 15/24 gives 0.625. Hence, 0.72222 is greater (13/18).

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3 years ago

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Marysya12 [62]

Answer:

Step-by-step explanation:

80 is less than 81, but more than 68.

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3 years ago

-8×3×(-2)×2×(-5) indicate if the answer is positive or negative

astraxan [27]

Answer:

The answer would be

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3 years ago

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Given n(A) = 1300, n(A U B) = 2290, and n(A n B) = 360, find n(B).

Stels [109]

Answer:

n(B) = 1350

Step-by-step explanation:

Using Venn sets, we have that:

$n(A \cup B) = n(A) + n(B) - n(A \cap B)$

Three values are given in the exercise.

The other is n(B), which we have to find. So

$n(A \cup B) = n(A) + n(B) - n(A \cap B)$

$2290 = 1300 + n(B) - 360$

$940 + n(B) = 2290$

$n(B) = 2290 - 940 = 1350$

n(B) = 1350

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3 years ago