What is the relationship between distance, time and acceleration
1 answer:
You might be interested in
Answer:
(a) Angular acceleration is 1.112 rad/s².
(b) Average angular velocity is 2.78 rad/s .
Explanation:
The equation of motion in Rotational kinematics is:
θ = θ₀ + 0.5αt²
Here θ is angular displacement at time t, θ₀ is angular displacement at time t=0, t is time and α is constant angular acceleration.
(a) According to the problem, θ is 13.9 rad, θ₀ is zero as it is at rest and t is 5 s. Put these values in the above equation:
13.9 = 0 + 0.5α(5)²
α = 1.112 rad/s²
(b) The equation of average angular velocity is:
ω = Δθ/Δt
ω =
ω = 2.78 rad/s
Explanation:
The given data is as follows.
width = 100 m, speed = 3 m/s
So, minimum time required to cross the stream is calculated as follows.
t =
Also, in the same time the man has moved downstream by 50 meter.
Hence, distance traveled downstream is as follows.
d = velocity of river × t
=
=
= 1.5 m/s
Thus, we can conclude that the river is flowing by 1.5 m/s.