Answer: Option C
Explanation: Let's do a heavy simplification.
The kinetic energy of the bus is K = (m/2)*v^2
Where m is the mass of the bus, and v is the velocity of the bus.
When the brakes are used, we can do a linear relationship that gives us the distance that the bus needs to come to a full stop, and this will depend on the kinetical energy that the buss had just right before, so the distance that the bus moves after slamming on the brakes is:
D = K/F = ((m/2)*v^2)/F
Where F depends on the effectiveness of the brakes, as bigger F is, faster the bus comes to a full stop.
Now, if we double the velocity; we have:
D' = ((m/2)*(2*v)^2)/F = ((m/2)*4*v^2)/F = 4*(((m/2)*v^2)/F) = 4*D
D' = 4D
So the distance is quadrupled, then the correct option is C
