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3 years ago

Which situation results in the most attraction between two magnets?

Physics

2 answers:

murzikaleks [220]3 years ago

6 0

Answer:

Explanation:

Opposites attract, the north pole of one of the magnet is attracted to the south pole of the other magnet. Two north or south poles will repel away from each other.

gayaneshka [121]3 years ago

3 0

Answer:It is C

Explanation:i just did it and i got it right

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The angular velocity of a 755-g wheel 15.0 cm in diameter is given by the equation ω(t) = (2.00 rad/s2)t + (1.00 rad/s4)t 3. (a)

Lunna [17]

Answer:

The number of radians turned by the wheel in 2s is $\theta= 8\ radians$

The angular acceleration is $\alpha =14 rad/s^2$

Explanation:

The angular velocity is given as

$w(t) = (2.00 \ rda/s^2)t + (1.00 rad /s^4)t^3$

Now generally the integral of angular velocity gives angular displacement

So integrating the equation of angular velocity through the limit 0 to 2 will gives us the angular displacement for 2 sec

This is mathematically evaluated as

$\theta(t ) = \int\limits^2_0 {2t + t^3} \, dt$

$= [\frac{2t^2}{2} + \frac{t^4}{4}] \left\{ 2} \atop {0}} \right.$

$= [\frac{2(2^2)}{2} + \frac{2^4}{4}] - 0$

$= 4 +4$

$\theta= 8\ radians$

Now generally the derivative of angular velocity gives angular acceleration

So the value of the derivative of angular velocity equation at t= 2 gives us the angular acceleration

This is mathematically evaluated as

$\frac{dw}{dt} = \alpha (t) = 2 + 3t^2$

so at t=2

$\alpha (2) = 2 +3(2)^2$

$\alpha =14 rad/s^2$

7 0

3 years ago

Ariana is heating a beaker of water. She notices that the water at the bottom

RSB [31]

B will be the answer ( Radiation)

6 0

4 years ago

An astronaut rides in a circular training accelerator at 16 m/s. If the radius of the accelerator is 8.0 meters, what is his cen

iren [92.7K]

Answer:

$a=32\ m/s^2$

Explanation:

Given that,

The velocity of an astronaut in a circular path, v = 16 m/s

The radius of the accelerator, r = 8 m

We need to find his centripetal acceleration. The formula that is used to find the centripetal acceleration is given by :

$a=\dfrac{v^2}{r}\\\\a=\dfrac{(16)^2}{8}\\\\a=32\ m/s^2$

So, the required centripetal acceleration is $32\ m/s^2$ .

7 0

3 years ago

A stone is dropped from a bridge 45 meters above the surface river. It takes the stone 4.6 seconds to reach the water surface. F

Hunter-Best [27]

The most interesting thing about this problem is that in order to use all of the given information, you need to ignore the laws of Physics, and never mind what the stone would really do if dropped from a real bridge in the real world.

Average velocity = (displacement) / (time for the displacement)

Displacement =
Straight path from the start point to the finish point = 45 meters down .
Time = 4.6 seconds

Average velocity = 45/4.6 = <em>9.783 meters/second down</em>

==================================

In the real world, a dropped stone would only take 3.03 seconds
to fall 45 meters.

Alternatively, a stone that fell for 4.6 seconds from rest would fall
103.7 meters, with an average velocity of 22.5 meters/second down.

But we accepted the given information, and did the best we could do
with it.

7 0

3 years ago

Read 2 more answers

What structure holds donor sperm in earthworms

lidiya [134]

Answer:

Explanation: As the earthworm passes through the slime tube, the tube will pass over the female pore picking up eggs. The tube will continue to move down the earthworm and pass over the male pore called the spermatheca which has the stored sperm called the spermatozoa.

4 0

3 years ago