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Setler [38]
3 years ago
11

Alan works in a gym. One week he recorded the number of people who

Mathematics
1 answer:
Svetlanka [38]3 years ago
4 0

your answer is 456 just calculate it up

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Helpp urgently need this
FrozenT [24]

Answer:

a

Step-by-step explanation:

4 0
3 years ago
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7 - 3x = 5x + 13. <br><br> What is x?
eduard

Answer:

x= -3/4 or -0.75

Step-by-step explanation:

1) subtract 7 from both sides which would make it

-3x= 5x+6

2) Subtract 5x from both sides which would make it

-8x-6

3) Divide both sides by -8

which gives you -3/4

7 0
3 years ago
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Which expression is equivalent to 10k+17-7j-18-11k?
balu736 [363]

Answer:

B. -7j-k-1

Step-by-step explanation:

Simplify:

1. IDENTIFY LIKE TERMS

<em>10k</em>+17-7j-18-<em>11k</em>

  • <em>10k and -11k are like terms since they have the same variable.</em>
  • 17 and -18 are like terms since they are regular numbers.
  • -7j has no like terms.

2. COMBINE LIKE TERMS

-7j-<em>k</em>-1

3 0
3 years ago
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HURRRYYYYYY Solve for t. 4/3 = t/7
VladimirAG [237]

Answer:

Step-by-step explanation:

4/3 = t/7

Multiply by 7 on both sides

4/3 x 7 = t

28/3 = t

3 0
3 years ago
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A motorist left town X at 08 00 for town Y situated 120km away, travelling at a constant speed of v km/hr, so as to arrive at Y
mote1985 [20]
<span>v = 45 km/hr u = 72 km/hr Can't sketch the graph, but can describe it. The Y-axis will be the distance. At the origin it will be 0, and at the highest point it will have the value of 120. The X-axis will be time in minutes. At the origin it will be 0 and at the rightmost point, it will be 160. The graph will consist of 3 line segments. They are 1. A segment from (0,0) to (80,60) 2. A segment from (80,60) to (110,60) 3. A segment from (110,60) to (160,120) The motorist originally intended on driving for 2 2/3 hours to travel 120 km. So divide the distance by the time to get the original intended speed. 120 km / 8/3 = 120 km * 3/8 = 360/8 = 45 km/hr After traveling for 80 minutes (half of the original time allowed), the motorist should be half of the way to the destination, or 120/2 = 60km. Let's verify that. 45 * 4/3 = 180/3 = 60 km. So we have a good cross check that our initial speed was correct. v = 45 km/hr Now having spent 30 minutes fixing the problem, out motorist now has 160-80-30 = 50 minutes available to travel 60 km. So let's divide the distance by time: 60 / 5/6 = 60 * 6/5 = 360/5 = 72 km/hr So the 2nd leg of the trip was at a speed of 72 km/hr</span>
6 0
3 years ago
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