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2 years ago

Please find the range and domain of the functions.

Mathematics

2 answers:

Bezzdna [24]2 years ago

8 0

Answer: are there any answer choices or anything to show so I can solve???!

Mariulka [41]2 years ago

3 0

what do the problems look like?

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$27 for four large pizzas or $32 for five large pizzas

frez [133]

Answer: $27 for four large pizzas is cheaper than 32$ for five large pizzas

Step-by-step explanation:

4 0

1 year ago

Read 2 more answers

PLEASE HELP!!!!!! I will give points

Vlada [557]

Answer:

Of the basketball players on the team, exactly 75% of the players have heights above 180

Step-by-step explanation:

So, they are 12 basketball players in total

1 - 170 - This is 1/12

2 - 175 - This is 1/6

1 - 180 - This is 1/12

4- 185 - This is 1/3

3 - 190 - This is 1/4

1 - 195 - This is 1/12

75% (Or 3/4) have heights above 180

Therefore, the answer is B

8 0

2 years ago

My brother wants to estimate the proportion of Canadians who own their house.What sample size should be obtained if he wants the

AVprozaik [17]

Answer:

a) $n=\frac{0.675(1-0.675)}{(\frac{0.02}{1.64})^2}=1475.07$

And rounded up we have that n=1476

b) $n=\frac{0.5(1-0.5)}{(\frac{0.02}{1.64})^2}=1681$

And rounded up we have that n=1681

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

If solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

Part a

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by $\alpha=1-0.9=0.1$ and $\alpha/2 =0.05$ . And the critical value would be given by:

$z_{\alpha/2}=\pm 1.64$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.02$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

And replacing into equation (b) the values from part a we got:

$n=\frac{0.675(1-0.675)}{(\frac{0.02}{1.64})^2}=1475.07$

And rounded up we have that n=1476

Part b

For this case since we don't have a prior estimate we can use $\hat p =0.5$

$n=\frac{0.5(1-0.5)}{(\frac{0.02}{1.64})^2}=1681$

And rounded up we have that n=1681

8 0

2 years ago

The perimeter of the original rectangle is ______

sergey [27]

Answer:

perimter of original rectangle = 17. 6 mm
side length of the enlarged rectangle = 23. 22 mm
perimeter of the enlarged rectangle = 95. 04 mm

Step-by-step explanation:

PERIMETER OF ORIGINAL RECTANGLE

Length of original rectangle = 4.5 mm
Width of original rectangle = 4.3 mm

perimeter = 2 × ( length + width)

= 2 × ( 4.5 + 4.3)

= 2 × 8.8

= 17. 6 mm

SIDE LENGTH OF ENLARGED RECTANGLE

Width of original rectangle = 4. 5 mm
Width of enlarged rectangle = 24.3 mm

Enlargement factor = 24.3 / 4.5

= 5.4

Length of original rectangle = 4.5 mm
Enlargement factor = 5.4

Side length of enlarged rectangle

= original length × Enlargement factor

= 4.3 × 5.4

= 23. 22 mm

PERIMTER OF ENLARGED RECTANGLE

= 2 × ( enlarged ength + enlarged breadth)

= 2 × (23. 22 + 24. 3 )

= 95. 04 mm

8 0

2 years ago

I need help on this question

Kitty [74]

What is the question? i think that’s important

8 0

2 years ago