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xxTIMURxx [149]
3 years ago
9

What is the value of a in the expression 7 to the power of d = of 3 square root of 7?

Mathematics
1 answer:
Elina [12.6K]3 years ago
3 0
The answer to w<span>hat is the value of a in the expression 7 to the power of d = of 3 square root of 7 is  a=19.</span>
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Can someone please help me this this??
Brrunno [24]

Answers:

bio = 258

sociology = 169

============================================================

Work Shown:

x = number of bio textbooks

y = number of sociology textbooks

x+y = 427 books sold total

y = x-89 since 89 less sociology textbooks were sold compared to bio

Apply substitution to get the following

x+y = 427

x+x-89 = 427 ... replace y with x-89

2x-89 = 427

2x = 427+89

2x = 516

x = 516/2

x = 258 bio textbooks were sold

y = x-89

y = 258-89

y = 169 sociology textbooks were sold

5 0
1 year ago
Need help please anything will help.!!!?!?!
yaroslaw [1]

Answer:

84.78 cubic feet it is the correct answer

please mark brainlist

8 0
3 years ago
How does the division rule for exponents help in understanding why anything to the zero power is 1?
Nookie1986 [14]
In the division rule you subtract the exponents<span> when </span>dividing<span> numbers with the same base. </span>One<span> rule for exponents is that exponents add when you have the same base. This works for any number x that you want to plug in except for x = </span>0<span>,because </span>0/0<span> is indeterminate (it is like dividing </span>zero<span> by </span>zero<span>). No matter what number we use when it is raised to the </span>zero power<span> it will always be </span>1.
5 0
3 years ago
Find gradient <br><br>xe^y + 4 ln y = x² at (1, 1)​
cricket20 [7]

xe^y+4\ln y=x^2

Differentiate both sides with respect to <em>x</em>, assuming <em>y</em> = <em>y</em>(<em>x</em>).

\dfrac{\mathrm d(xe^y+4\ln y)}{\mathrm dx}=\dfrac{\mathrm d(x^2)}{\mathrm dx}

\dfrac{\mathrm d(xe^y)}{\mathrm dx}+\dfrac{\mathrm d(4\ln y)}{\mathrm dx}=2x

\dfrac{\mathrm d(x)}{\mathrm dx}e^y+x\dfrac{\mathrm d(e^y)}{\mathrm dx}+\dfrac4y\dfrac{\mathrm dy}{\mathrm dx}=2x

e^y+xe^y\dfrac{\mathrm dy}{\mathrm dx}+\dfrac4y\dfrac{\mathrm dy}{\mathrm dx}=2x

Solve for d<em>y</em>/d<em>x</em> :

e^y+\left(xe^y+\dfrac4y\right)\dfrac{\mathrm dy}{\mathrm dx}=2x

\left(xe^y+\dfrac4y\right)\dfrac{\mathrm dy}{\mathrm dx}=2x-e^y

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2x-e^y}{xe^y+\frac4y}

If <em>y</em> ≠ 0, we can write

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2xy-ye^y}{xye^y+4}

At the point (1, 1), the derivative is

\dfrac{\mathrm dy}{\mathrm dx}\bigg|_{x=1,y=1}=\boxed{\dfrac{2-e}{e+4}}

4 0
3 years ago
What is this question?? (needing help)
Free_Kalibri [48]

468 x 0.001 = 0.468

46.8 x 0.1 = 4.68

4.68 x 10^3 = 4680

0.468 x 10^2 = 46.8

Hope this helps!

5 0
3 years ago
Read 2 more answers
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