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stich3 [128]
3 years ago
7

What is defect of vision​

Physics
1 answer:
Anuta_ua [19.1K]3 years ago
4 0

Answer:

The vision becomes blurred due to the refractive defects of the eye. There are mainly three common refractive defects of vision. These are (i) myopia or near-sightedness, (ii) Hypermetropia or far – sightedness, and (iii) Presbyopia. These defects can be corrected by the use of suitable spherical lenses.

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Two identical conducting spheres are placed 80.0 cm apart. One is given a charge of 5.8 C and the other is given a charge of 6.4
Zepler [3.9K]

Answer: 5.214(10)^{11} N

Explanation:

According to <u>Coulomb's Law:</u>  

<em>"The electrostatic force F_{E} between two point charges q_{1} and q_{2} is proportional to the product of the charges and inversely proportional to the square of the distance d that separates them, and has the direction of the line that joins them".</em>

<em />

Mathematically this law is written as:

F_{E}=K\frac{q_{1}.q_{2}}{d^{2}}  

Where:

F_{E}  is the electrostatic force

K=8.99(10)^{9} Nm^{2}/C^{2} is the Coulomb's constant  

q_{1}=5.8 C and q_{2}=6.4 C are the electric charges

d=80 cm \frac{1 m}{100 cm}=0.8 m is the separation distance between the charges

Solving:

F_{E}=8.99(10)^{9} Nm^{2}/C^{2}\frac{(5.8 C)(6.4 C)}{(0.8 m)^{2}}  

F_{E}=5.214(10)^{11} N    

7 0
4 years ago
To a stationary observer, a bus moves south with a speed of 12 m/s. A man
crimeas [40]

ANSWER

C 11.5 m/s

EXPLANATION

6 0
3 years ago
A 50n brick is suspended by a light string from a 30kg pulley which may be considered a solid disk with radius 2.0m. the brick i
igomit [66]

Brick is held at a position which is at height 2 m from the floor

Now it is released from rest and hit the floor after t = 4 s

Now the acceleration of the brick is given by

y = v_i* t + 0.5 at^2

2 = 0 + 0.5 * a * 4^2

a = 0.25 m/s^2

a)

Now in order to find the tension in the string

we can use Newton's law

F_{net} = ma

mg - T = ma

50 - T = \frac{50}{9.8}*0.25

T = 48.72 N

part b)

Now for the pulley

moment of inertia= \frac{1}{2}mr^2

m = 30 kg

R = 2 m

I = \frac{1}{2}*30*2^2

I = 60 kg m^2

Now the angular speed just before brick collide with the floor

w = \frac{v}{r}[\tex]here we have[tex]v = v_i + a* t

v = 0 + 0.25 * 4

v = 1 m/s

Now we will have

L = angular momentum = I w = I*\frac{v}{R}

L = 60 *\frac{1}{2}

L = 30 kg m^2/s

8 0
3 years ago
Problem 5 A block of mass 3 kg slides on a horizontal, rough surface towards a spring with k = 500 N/m. The kinetic friction coe
vredina [299]

Answer:

Explanation:

given,

mass of block = 3 kg

spring constant k = 500 N/m

kinetic friction coefficient µk = 0.6

speed of block = 5 m/s

F = µk  N

F = 0.6 x 3 x 9.8

F = 17.64 N

using energy conservation

\dfrac{1}{2}mv^2=\dfrac{1}{2}kx^2+Fx

\dfrac{1}{2}\times 3 \times 5^2=\dfrac{1}{2}\times 500 \times x^2+17.64\times x

250 x² + 17.64 x - 37.5 = 0

on solving

x = 0.354 m

graph is attached below

4 0
4 years ago
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Who participates in sport more? women or men and why?
Katen [24]
More women ...........I'm not sure why
6 0
4 years ago
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