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svetlana [45]
2 years ago
11

I need this done pls

Physics
1 answer:
Aleonysh [2.5K]2 years ago
5 0

Answer:

all the details are in the attached picture, the answers are marked with colour.

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The greater the amplitude of a wave a. The quieter the sound b. The higher the frequency of the sound c. The dimmer the light in
Stolb23 [73]

Answer:

The greater the amplitude the greater the energy.

(Think of a water wave - which carries greater energy a 1 ft wave or

a 10 ft wave)

8 0
3 years ago
what is the main reason that attitudes are more often revealed in spoken rather than written language
pishuonlain [190]
It's a combination of all those things. probably because we are taught from an early age to write in an academic fashion, giving balanced arguments and a conclusion. When speaking from the heart, there is no opposing argument nor is there a conclusion, just emotion.
5 0
3 years ago
Points A (-5,6), B (2,-2), and C (-6,-3) are placed in three different quadrants of a Cartesian coordinate system. Convert each
AURORKA [14]

Answer: A (\sqrt{61},309.8°)

              B (2\sqrt{2}, 315°)

             C (3\sqrt{5}, 26.56°)

Explanation: To transform rectangular coordinates into polar coordinates use:

r=\sqrt{x^{2}+y^{2}} and \theta=tan^{-1}(\frac{y}{x})

For point A:

r=\sqrt{(-5)^{2}+6^{2}}

r=\sqrt{61}

\theta=tan^{-1}(\frac{6}{-5})

\theta=tan^{-1}(-1.2)

\theta=-50.2°

Point A is in the II quadrant, so we substract the angle for 360° since it is in degrees:

\theta=360-50.2

\theta= 309.8°

Polar coordinates for point A is (\sqrt{61}, 309.8°)

For point B:

r=\sqrt{2^{2}+(-2)^{2}}

r=\sqrt{8}

r=2\sqrt{2}

\theta=tan^{-1}(\frac{-2}{2} )

\theta=tan^{-1}(1)

\theta=-45°

Point B is in IV quadrant, so:

\theta=360-45

\theta= 315°

Polar coordinates for point B is (2\sqrt{2}, 315°)

For point C:

r=\sqrt{(-6)^{2}+(-3)^{2}}

r=\sqrt{45}

r=3\sqrt{5}

\theta=tan^{-1}(\frac{-3}{-6} )

\theta=tan^{-1}(0.5)

\theta= 26.56°

Polar coordinates for point C is (3\sqrt{5}, 26.56°)

3 0
3 years ago
Which of the following statements is not one of Newton's laws of motion?
Alex17521 [72]

Answer:

The answer to your question: d.

Explanation:

a. The rate of change of momentum of an object is equal to the net force applied to the object.  

This is the second a law of motion, so this answer is incorrect.

b. In the absence of a net force acting on it, an object moves with constant velocity.

This is the first Newton law of motion, so this option is not correct.

c. For any force, there always is an equal and opposite reaction force.

This is the third law of motion, so this is not the right option.

d. What goes up must come down.

Newton said this sentence, but is not part of the law of motion.

5 0
3 years ago
Do the data for the first part of the experiment support or
mrs_skeptik [129]

Answer:

your the class suru and Sahiba and Sahiba are all guddu saifi and Mam aap Aman and Sahiba are not

7 0
3 years ago
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