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3 years ago

12

A car travels 35 miles in 3 hours. At this rate, how many miles will the car travel in ½ hour? (Convert answer to a fraction)

1 answer:

Ber [7]3 years ago

3 0

Answer:

5 5/6 miles

Step-by-step explanation:

There are a few ways to do this, but one way is to find out how many miles per hour the car can travel. For this we do 35/3(distance/time) which is 11 2/3 mph. Now, to find half an hour we can divided 11 2/3 divided by 2, which is

5 5/6 miles.

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Pls help with number 3

Arturiano [62]

Answer:

about 17

Step-by-step explanation:

side 1 =4

side 2=4

side 3=4

one of the slanted lines is about equal to 2 and the other is also about 2

but i rounded it to 17 because a slanted line is longer than one that is straight across

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Can a triangle be made with sides of length 7, 10, and 20 units?

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A water trough has two congruent isosceles trapezoids as ends and two congruent rectangles as sides. The exterior surface area o

andriy [413]

Answer:

Part a) The exterior surface area is equal to $160\ ft^{2}$

Part b) The volume is equal to $240\ ft^{3}$

Part c) The volume water left in the trough will be $84\ ft^{3}$

Step-by-step explanation:

Part a) we know that

The exterior surface area is equal to the area of both trapezoids plus the area of both rectangles

so

<em>Find the area of two rectangles</em>

$A=2[12*5]=120\ ft^{2}$

<em>Find the area of two trapezoids</em>

$A=2[\frac{1}{2}(8+2)h]$

Applying Pythagoras theorem calculate the height h

$h^{2}=5^{2}-3^{2}\\h^{2}=16\\h=4\ ft$

substitute the value of h to find the area

$A=2[\frac{1}{2}(8+2)(4)]=40\ ft^{2}$

The exterior surface area is equal to

$120\ ft^{2}+40\ ft^{2}=160\ ft^{2}$

Part b) Find the volume

we know that

The volume is equal to

$V=BL$

where

B is the area of the trapezoidal face

L is the length of the trough

we have

$B=20\ ft^{2}\\ L=12\ ft$

substitute

$V=20(12)=240\ ft^{3}$

Part c)

step 1

Calculate the area of the trapezoid for h=2 ft (the half)

the length of the midsegment of the trapezoid is (8+2)/2=5 ft

$A=\frac{1}{2}(5+2)(2)=7\ ft^{2}$

step 2

Find the volume

The volume is equal to

$V=BL$

where

B is the area of the trapezoidal face

L is the length of the trough

we have

$B=7\ ft^{2}\\ L=12\ ft$

substitute

$V=7(12)=84\ ft^{3}$

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