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Furkat [3]
2 years ago
6

Create polynomial functions using the given information:

Mathematics
1 answer:
ycow [4]2 years ago
8 0

It's pretty much simple. Since we can factor a polynomial by its zeros, lets write one of degree nine :

X(X-1)(X-2)(X-3)(X-4)(X-5)(X+1)(X+2)(X+3)= X^9-9X^8+6X^7+126X^6-231X^5-441X^4+944X^3+324X^2-720X

This polynomial is of degree 9 and has exactly 5 strictly positive zeros : 1, 2, 3, 4, 5

And it has 3 negative zeros : - 1, -1, - 3

And it has 0 as a zero too.

There is also this one :

(X-1)(X-2)(X-3)(X-4)(X²+1)(X+1)(X+2)(X+3) = X^9-4X^8-13X^7+52X^6+35X^5-140X^4+13X^3-52X^2-36X+144

It has 4 positive zeros : 1, 2, 3, 4.

It has complex zeros : i and - i

3 negative zeros : - 1, - 2 , - 3

Good Luck

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Height of the water increasing is at rate of  #(dh)/(dt)=3/(25 pi)m/(min)#

<h3>How to solve?</h3>

With related rates, we need a function to relate the 2 variables, in this case it is clearly volume and height. The formula is:

#V=pi r^2 h#

There is radius in the formula, but in this problem, radius is constant so it is not a variable. We can substitute the value in:

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Since the rate in this problem is time related, we need to implicitly differentiate wrt (with respect to) time:

#(dV)/(dt)=(25 m^2) pi (dh)/(dt)#

In the problem, we are given #3(m^3)/min# which is #(dV)/(dt)#.

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#(dh)/(dt)=(3m^3)/(min (25m^2) pi)=3/(25 pi)m/(min)#

Hence,  Height of the water increasing is at rate of  #(dh)/(dt)=3/(25 pi)m/(min)#

<h3>Formula used: </h3>

#V=pi r^2 h#

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