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kolezko [41]
3 years ago
15

Hi, I need help on the chemical names of the following two:

Chemistry
1 answer:
Lesechka [4]3 years ago
3 0

Answer:

like how do you need help

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If you need 2.5 moles of Rb2Cr7, how many grams do you need?
BartSMP [9]

Answer:

0

Explanation:

5 0
3 years ago
What is not true of a strong base? A. It must have a concentration above 1.0 M. B. It is always a strong electrolyte in water. C
Rashid [163]
The choices are true about the characteristic of a strong base, except for it having a concentration of above 1.0 M. Therefore, the answer is letter A. The concentration of the base is not a very important as to how strong really the base is. 
4 0
3 years ago
Read 2 more answers
Homework . Answered
bija089 [108]

We have that the name (not chemical symbol) of the main group element in period 5 and group 3A is

Metalloid boron (B)

From the Question we are told that

The element belongs to

Period 5 and group 3A

Generally

Group 3A of the periodic table includes the metalloid boron (B),   aluminum (Al), indium (In), and thallium (Tl) gallium (Ga),

Period 5 is possessed by the metalloid boron (B) of the Group 3A

For more information on this visit

brainly.com/question/13025901?referrer=searchResults

7 0
3 years ago
The reaction H2SO4 + 2 NaOH -> Na2SO4 + 2H2O applied to an acid-base tritration. The equivalence point occurs when 26.66 mL o
bazaltina [42]
We make use of ratios to solve this question.
            moles NaOH = c · V = 0.1923 mmol/mL · 26.66 mL = 5.126718 mmol
            moles H2SO4 = 5.126718 mmol NaOH · 1 mmol H2SO4 / 2 mmol NaOH = 2.563359 mmol
Hence
            [H2SO4]= n/V = 2.563359 mmol / 42.45 mL = 0.06039 M
The answer to this question is  [H2SO4] = 0.06039 M

8 0
3 years ago
How many moles of ammonium ions are in 6.965 g of ammonium carbonate? Express your answer using four significant figures.
bekas [8.4K]

Answer:

there are 3.63*10⁻² moles of ammonium anions

Explanation:

since the ammonium carbonate is

(NH₄)₂(CO₂)

and the ammonium carbonate dissociate according to

(NH₄)₂(CO₂) →2*NH₄⁺ + CO₂²⁻  ( we will neglect other carbonate species for simplicity)

then each mole of ammonium carbonate generates 2 moles of ammonium anions , then

n AC = 2* n A

where n represents moles AC represents ammonium carbonate and A represents ammonium anions

also we know that

n AC = m AC / M AC

where

m = mass of ammonium carbonate = 6.595 g

M  = molecular weight of ammonium carbonate = 96.09 g/mol

then

n AC = m AC / M AC = 6.595 g/ 96.09 g/mol = 7.25*10⁻² moles of ammonium carbonate

thus

n AC = 2* n A → n A = n AC /2 = 7.25*10⁻² /2 = 3.63*10⁻² moles of ammonium anions

3 0
4 years ago
Read 2 more answers
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