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Likurg_2 [28]
3 years ago
12

Write a paragraph of no less than five sentences explaining how Newton's First Law of Motion supports people's need to wear seat

belts when riding in a moving car. Remember to use proper grammar and mechanics when writing your paragraph.
Physics
1 answer:
Inessa [10]3 years ago
7 0
Newton's first law can be taken to mean that if something is moving it tends to keep moving. if at rest it tends to stay at rest.

so, in a car, you and the car are both moving, say at constant speed. Now you're not actually connected to the car as in clamped to it, not yet at least. You're simply sitting in it at rest with respect to it.

but, someone slams on the brakes for whatever reason. The car slows down/stops. what do you do ? well, you would keep going. and moving a few feet in a car can be dangerous, esp if you're moving at high speed. Unless of course you're clamped to the seat, and the seat is clamped to the car and the car is clamped together. then when the car brakes, yes you'll feel the braking effect, but the belt will restrict your movement, keeping you safe, if shocked and bruised.
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A 2.3 m long wire weighing 0.075 N/m is suspended directly above an infinitely straight wire. The top wire carries a current of
ZanzabumX [31]

Answer:

Explanation:

Magnetic field near current carrying wire

= \frac{\mu_0}{4\pi} \frac{2i}{r}

i is current , r is distance from wire

B =  10⁻⁷ x \frac{2\times49}{r}

force on second wire per unit length

B I L , I is current in second wire , L is length of wire

=  10⁻⁷ x \frac{2\times49}{r} x 33 x 1

= 3234 x \frac{10^{-7}}{r}

This should balance weight of second wire per unit length

3234 x \frac{10^{-7}}{r} = .075

r = \frac{3234}{.075} x 10⁻⁷

= .0043 m

= .43 cm .

5 0
3 years ago
Two particles execute simple harmonic motion of the same amplitude and frequency along close parallel lines. They pass each othe
deff fn [24]

Answer:

\theta_2 - \theta_1 = 156.93 degree

Explanation:

As we know that the displacement of the particle from the mean position is 1/5 times of its amplitude

so we have

y = A sin\omega t

y = \frac{A}{5}

so now we have

\frac{A}{5} = A sin\omega t

now we have

\theta_1 = 11.53 degree

so the phase other particle in opposite direction is given as

\theta_2 = 180 - 11.53 = 168.46 degree

so we have phase difference given as

\theta_2 - \theta_1 = 168.46 - 11.53

\theta_2 - \theta_1 = 156.93 degree

7 0
3 years ago
Two ships of equal mass are 110 m apart. What is the acceleration of either ship due to the gravitational attraction of the othe
dusya [7]

Answer:

Acceleration of the ship, a=2.14\times 10^{-7}\ m/s^2

Explanation:

It is given that,

Mass of both ships, m=39000\ metric\ tons=39\times 10^6\ kg

Distance between two ships, d = 110 m

The gravitational force between two ships is given by :

F=G\dfrac{m^2}{d^2}

F=6.67\times 10^{-11}\ Nm^2/kg^2\times \dfrac{(39\times 10^6\ kg)^2}{(110\ m)^2}

F = 8.38 N

Let a is the acceleration. Now, using second law of motion as :

a=\dfrac{F}{m}

a=\dfrac{8.38\ N}{39\times 10^6\ kg}

a=2.14\times 10^{-7}\ m/s^2

So, the acceleration of either ship due to the gravitational attraction of the other is 2.14\times 10^{-7}\ m/s^2. Hence, this is the required solution.

7 0
3 years ago
A toy car has 2A of current if the car runs one four <br>1.5V batteries, what is the resistance?​
lesya [120]

Answer:

3 ohm

Explanation:

Resistance = Voltage/Current

= 6.0/2

= <u>3</u><u> </u><u>o</u><u>h</u><u>m</u>

5 0
3 years ago
A piece of plastic is uniformly charged with surface charge density eta1. The plastic is then broken into a large piece with sur
Amiraneli [1.4K]
C is the answer for this problem
3 0
3 years ago
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