Answer:
If thermal energy is the motion energy of the particles of a substance, which has more thermal energy—the cup of hot tea or a spoonful of hot tea? It makes sense that the more particles of a substance you have, then the more thermal energy the substance has. The cup of hot tea would have more thermal energy, even if the temperature of the tea is the same in the cup and in the spoon. But which cools down the quickest (has the highest rate of thermal energy transfer)—the tea in the cup or the tea in the spoon? If I have fewer particles of the same substance, then the rate of thermal energy transfer is faster. The tea in the spoon would lose thermal energy more rapidly. So the amount of a substance you have is one factor that affects the rate of thermal energy transfer.
Explanation:
Answer A is incorrect
A crest is just one point. It is not the distance between 2 crests.
B is incorrect
A trough is just 1 point. It is not the distance between 2 troughs.
C is incorrect.
the amplitude measures the height of a crest from the middle of the wave to the crest (or trough).
D is the correct answer. That is the distance between 2 crests or 2 troughs
You should just ask the wave
Answer:
area = 5733.33 cm²
length = 5.47 ×
cm
Explanation:
Given data
density = 19.32 g/cm³
mass = 33.16 g
thickness = 3.000 µm = 3 ×
cm
radius r = 1.000 µm = 1 × cm
to find out
area of the leaf and length of the fiber
solution
we know volume formula that is
volume = mass / density
volume = 33.16 / 19.32
volume = 1.72 cm³
we know that volume = thickness × area
so area
area = volume / thickness
area = 1.72 / 3 ×
area = 5733.33 cm²
and
we know volume = πr²L
so L = volume / πr²
length = 1.72 / π(1×)²
length = 5.47 × cm
Answer:
v = 17.71 m / s
Explanation:
We can work this exercise with the kinematics equations. In general the body is released so that its initial velocity is zero, the acceleration of the acceleration of gravity
v² = v₀² - 2 g (y -y₀)
v² = 0 - 2g (y -y₀)
when it hits the stone the height is zero and part of the height of the seagull I
v² = 2g y₀
v = Ra (2g i)
let's calculate
v =√ (2 9.8 16)
v = 17.71 m / s
