Question

A car moving in a straight line starts at x=0 at t=0. it passes the point x=25.0m with a speed of 11.0m/s at t=3.0s. it passesthe point x=385m with a speed of 45.0m/s at t=20.0s. find the average velocity and the average acceleration, between t=3.0s and t=20.0s

Answer 1

Between time 3 second to 20 seconds the time difference = 17 seconds

Distance traveled = 385 - 25 = 360 m

So average velocity = 360/17 = 21.18 m/s

Change in velocity at t =3 seconds and t = 20 seconds is given by 45 - 11 = 34 m/s

So average acceleration = 34/17 = 2  m/s