Explanation:
It is given that,
The mass of bob, m = 77 kg
Length of the string, L = 10 m
Angle made by the string with the vertical, 
(a) Let T is the force exerted by the string on the pendulum. At equilibrium,



T = 755.63 N
The horizontal component of the force is given by,


The vertical component of the force is given by,


(b) Let a is the radial acceleration of the bob. It can be calculated as :



Hence, this is the required solution.
Answer:
a = 10.07m/s^2
Their acceleration in meters per second squared is 10.07m/s^2
Explanation:
Acceleration is the change in velocity per unit time
a = ∆v/t
Given;
∆v = 50.0miles/hour - 0
∆v = 50.0miles/hours × 1609.344 metres/mile × 1/3600 seconds/hour
∆v = 22.352m/s
t = 2.22 s
So,
Acceleration a = ∆v/t = 22.352m/s ÷ 2.22s
a = 10.07m/s^2
Their acceleration in meters per second squared is 10.07m/s^2
Since the temperature of the gas remains constant in the process, we can use Boyle's law, which states that for a gas transformation at constant temperature, the product between the gas pressure and its volume is constant:

which can also be rewritten as

(1)
where the labels 1 and 2 mark the initial and final conditions of the gas.
In our problem,

,

and

, so the final pressure of the gas can be found by re-arranging eq.(1):

Therefore the correct answer is
<span>1. 0.75 atm</span>
Answer: Reliable and trusted
Answer:
Current in outer circle will be 15.826 A
Explanation:
We have given number of turns in inner coil 
Radius of inner circle 
Current in the inner circle 
Number of turns in outer circle 
Radius of outer circle 
We have to find the current in outer circle so that net magnetic field will zero
For net magnetic field current must be in opposite direction as in inner circle
We know that magnetic field is given due to circular coil is given by

For net magnetic field zero

So 
