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2 years ago

What is the answer to this question?

Physics

1 answer:

icang [17]2 years ago

8 0

Answer:

Explanation:

In a velocity/time (aka acceleration) graph, the slope of a line indicates the value of the acceleration in m/s/s. Acceleration is the change in velocity over the change in time. From 0 - 2 seconds, there is no change in velocity, so the acceleration during this interval is 0 (which is the same as the slope of the line). From 2 - 4 seconds, the slope of the line is -2, so the acceleration during the time interval from 2 to 4 seconds is -2 (negative because David is slowing down but is still going the same direction: to the right).

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2. Consider a conical pendulum with a bob of mass m = 77.0 kg on a string of length L = 10.0 m that makes an angle of ???? 3.00°

bekas [8.4K]

Explanation:

It is given that,

The mass of bob, m = 77 kg

Length of the string, L = 10 m

Angle made by the string with the vertical, $\theta=3^{\circ}$

(a) Let T is the force exerted by the string on the pendulum. At equilibrium,

$T\ cos\theta=mg$

$T=\dfrac{mg}{cos\theta}$

$T=\dfrac{77\times 9.8}{cos(3)}$

T = 755.63 N

The horizontal component of the force is given by,

$T_H=T\ sin\theta$

$T_H=755.63\ sin(3)=39.54\ N$

The vertical component of the force is given by,

$T_V=T\ sin\theta=mg$

$T_V=754.59\ N$

(b) Let a is the radial acceleration of the bob. It can be calculated as :

$a=\dfrac{T_H}{m}$

$a=\dfrac{39.54\ N}{77\ kg}$

$a=0.51\ m/s^2$

Hence, this is the required solution.

6 0

2 years ago

Finally, you are ready to answer the main question. Cheetahs, the fastest of the great cats, can reach 50.0 miles/hour miles/hou

dolphi86 [110]

Answer:

a = 10.07m/s^2

Their acceleration in meters per second squared is 10.07m/s^2

Explanation:

Acceleration is the change in velocity per unit time

a = ∆v/t

Given;

∆v = 50.0miles/hour - 0

∆v = 50.0miles/hours × 1609.344 metres/mile × 1/3600 seconds/hour

∆v = 22.352m/s

t = 2.22 s

So,

Acceleration a = ∆v/t = 22.352m/s ÷ 2.22s

a = 10.07m/s^2

Their acceleration in meters per second squared is 10.07m/s^2

7 0

2 years ago

Read 2 more answers

A 6.5 l sample of nitrogen at 25◦c and 1.5 atm is allowed to expand to 13.0 l. the temperature remains constant. what is the fin

ollegr [7]

Since the temperature of the gas remains constant in the process, we can use Boyle's law, which states that for a gas transformation at constant temperature, the product between the gas pressure and its volume is constant:
$pV=k$
which can also be rewritten as
$p_1 V_1 = p_2 V_2$ (1)
where the labels 1 and 2 mark the initial and final conditions of the gas.

In our problem, $p_1 = 1.5 atm$ , $V_1 =6.5 L$ and $V_2 =13.0 L$ , so the final pressure of the gas can be found by re-arranging eq.(1):
$p_2 = p_1 \frac{V_1}{V_2}= (1.5 atm) \frac{6.5 L}{13.0 L}=0.75 atm$

Therefore the correct answer is
<span>1. 0.75 atm</span>

8 0

3 years ago

When doing scientific research ,the sources used should be ?

quester [9]

Answer: Reliable and trusted

6 0

3 years ago

Read 2 more answers

Two circular coils are concentric and lie in the same plane. The inner coil contains 170 turns of wire, has a radius of 0.0095 m

PIT_PIT [208]

Answer:

Current in outer circle will be 15.826 A