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Ierofanga [76]
3 years ago
8

Two students are preparing for a marathon. Hector ran 8 miles in 85 minutes. Mario ran 6 miles in 55 minutes. Who has the faster

average speed?
Mathematics
2 answers:
Stels [109]3 years ago
7 0
formula\ for\ average\ speed= \frac{distance}{time}\\\\
Hector:\\\\
v_H=\frac{8miles}{85\ minutes}\approx0,09\frac{mile}{min}\\\\
Mario:\\\\
v_M=\frac{6miles}{55minutes}=0,1\frac{miles}{min}\\\\
Mario\ has\ faster\ speed.
pishuonlain [190]3 years ago
3 0
Since v=d/t
We can change the times from minutes to hours so that the answers will be in mph (but it isn't necessary)
Hectors speed=8/1.42=5.6mph
Marios speed=6/0.92=6.5mph
Therefore mario has the greater average speed.
Hope this helps :-)
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The first-serve percentage of a tennis player in a match is normally distributed with a standard deviation of 4.3%. If a sample
dem82 [27]

The first-serve percentage of a tennis player in a match is normally distributed with a standard deviation of 4.3%. If a sample of 15 random matches of the player is taken, the mean first-serve percentage is found to be 26.4%. The margin of error of the sample mean is 83.71%.

7 0
3 years ago
There are 3 bags each containing 100 marbles. Bag 1 has 75 red and 25 blue marbles. Bag 2 has 60 red and 40 blue marbles. Bag 3
jekas [21]

Answer:

0.4 ; 0.6125

Step-by-step explanation:

Given the following :

Bag 1 : 75 red ; 25 blue

Bag 2: 60 red ; 40 blue

Bag 3: 45 red ; 55 blue

Probability = (required outcome / Total possible outcomes)

A) since the probability of choosing each bag is equal :

BAG A:

P(choosing bag A) = 1 / total number of bags = 1/3 ; P(choosing blue marble) = number of blue marbles / total number of marbles = 25/100

HENCE, choosing a blue marble from bag A : = (1/3 × 75/100) = 25/300

BAG B:

P(choosing bag B) = 1/3 ;

P(choosing blue marble) = number of blue marbles / total number of marbles = 40/100

HENCE, choosing a blue marble from bag A : = (1/3 × 40/100) = 40/300

BAG C:

P(choosing bag C) = 1/3

P(choosing blue marble) = number of blue marbles / total number of marbles = 55/100

HENCE, choosing a blue marble from bag A : = (1/3 × 55/100) = 55/300

= (25/300) × (40/300) × (55/300) = (25 + 40 + 55)/300 = 120/300 = 0.4

2) What is the probability that the marble is blue when the first bag is chosen with probability 0.5 and other bags with equal probability each?

BAG A:

P(choosing bag A) = 0.5 ; P(choosing blue marble) = number of blue marbles / total number of marbles = 25/100

HENCE, choosing a blue marble from bag A : = (0.5 × 75/100) = (0.5 * 0.75) = 0.375

BAG B:

P(choosing bag B) = (1-0.5) / 2 = 0.25 ;

P(choosing blue marble) = number of blue marbles / total number of marbles = 40/100

HENCE, choosing a blue marble from bag A : = (0.25 × 40/100) = (0.25 × 0.4) = 0.1

BAG C:

P(choosing bag C) = (1 - (0.5+0.25)) = 0.25

P(choosing blue marble) = number of blue marbles / total number of marbles = 55/100

HENCE, choosing a blue marble from bag A : = (0.25 × 55/100) = 0.25 × 0.55 = 0.1375

= 0.1375 + 0.1 + 0.375 = 0.6125

7 0
3 years ago
Please help!!<br>show work!!<br>please!!
Advocard [28]
\frac{1}{1} *  \frac{1}{3} would work. 
4 0
3 years ago
A survey was conducted on a random sample of 100
zalisa [80]

Answer:

No, he is not correct because red and yellow got the same amount of votes when it came to adding them up.

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Can someone help me?
Romashka [77]

Answer:

I hope this helps!

Step-by-step explanation:

1. M is .25

b is 20

so

y= .25x+20

2. y= 3x+2

6 0
3 years ago
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