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Whitepunk [10]
3 years ago
11

An architect measures a beam to be 96.55 centimeters long, with an accuracy of plus or minus 0.02 centimeter. Which equation can

be used to find the limits of the actual length of the beam? |x−96.55|=0.02start absolute value x minus 96 point 5 5 end absolute value is equal to 0 point 0 2 |96.55−0.02|=xstart absolute value 96 point 5 5 minus 0 point 0 2 end absolute value is equal to x |x+96.55|=0.02start absolute value x plus 96 point 5 5 end absolute value is equal to 0 point 0 2 |96.55+0.02|=x
Mathematics
1 answer:
olga2289 [7]3 years ago
3 0

Answer:

|96.55−0.02|= x

|96.55+0.02|=x

Step-by-step explanation:

Given that:

Measured length of beam = 96.55 cm

Measurement accuracy = plus or minus (± 0.02cm)

Limits of actual length of the beam:

Let limit of actual length = x

Lower limit :

|measured length - accuracy| = x

|96.55 - 0.02| = x

96.53) x

Upper limit :

|measured length + accuracy| = x

|96.55 + 0.02| = x

96.57 = x

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Angelina_Jolie [31]

Answer:

Total possible number of outcomes = C(24,6) [24 choose 6]

=24!/(6!18!)

= 134596

Out of which there is only one winning combination.

Therefore we conclude:

P(win 20000)=1/134596

P(lose 1)=134595/134596

and hence the expected value is:

20000*(1/134596)+(-1)*(134595/134596)

=-114595/134596

=-0.8514 (rounded to four places after decimal)

Step-by-step explanation:

Hope this helped!

8 0
3 years ago
What is the Kinetic energy of a 2000 kg bus that is moving at 30m/s? <br><br> Explain please
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There's a formula for that.

KE = (1/2)mv²

... = (1/2)(2000 kg)(30 m/s)²

... = 900,000 kg·m²/s²

... = 900,000 J

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4 0
3 years ago
A student union cafeteria worker checked the weight of ten half-pound bags of whole bean coffee and recorded the following weigh
Likurg_2 [28]

Answer: σ = 0.0154

Step-by-step explanation:

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(0.48 + 0.51 + 0.47 + 0.49 + 0.49 + 0.50 + 0.52 + 0.48 + 0.49 + 0.51)/10 =

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The mean is represented with the greek letter μ, so μ = 0.49

2. For each element in the serie, subtract the mean (0.49) and square the result

(0.48 - 0.49)^2 = (-0.01)^2 = 0.0001

(0.51 - 0.49)^2 = (0.02)^2 = 0.0004

(0.47 - 0.49)^2 = (-0.02)^2 = 0.0004

(0.49 - 0.49)^2 = 0

(0.49 - 0.49)^2 = 0

(0.50 - 0.49)^2 = (0.01)^2 = 0.0001

(0.52 - 0.49)^2 = (0.03)^2 = 0.0009

(0.48 - 0.49)^2 = (-0.01)^2 = 0.0001

(0.49 - 0.49)^2 = 0

(0.51 - 0.49)^2 = (0.02)^2 = 0.0004

So we get these results: 0.0001, 0.0004, 0.0004, 0, 0, 0.0001, 0.0009, 0.0001, 0, 0.0004

3. Now, we calculate the mean of these squared differences

(0.0001 + 0.0004 + 0.0004 + 0 + 0 + 0.0001 + 0.0009 + 0.0001 + 0 + 0.0004) / 10 =

(0.0024) / 10 = 0.00024

4. Now to get the standard deviation, we need to get the root of this last value (0.00024).

√(0.00024) = 0.0154

5. So that will be our standard deviation value:

σ = 0.0154

DONE!

7 0
3 years ago
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ira [324]

Answer:

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Given that;

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Using the Poisson probability formula;

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