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Ne4ueva [31]
3 years ago
6

A football player kicks a football in a field goal attempt. When the football reaches its maximum height, what is the relationsh

ip between the direction of the velocity and acceleration vectors? Assume air resistance is negligible.
A)A football player kicks a football in a field goal attempt. When the football reaches its maximum height, what is the relationship between the direction of the velocity and acceleration vectors? Assume air resistance is negligible.
B) At the maximum height, the velocity and acceleration vectors are parallel to each other.
C)At the maximum height, the velocity and acceleration vectors are perpendicular to each other.
D)At the maximum height, the velocity and acceleration vectors point in opposite directions.
E)At the maximum height, both the velocity and acceleration vectors are zero
Physics
2 answers:
RideAnS [48]3 years ago
8 0

Answer: C) At the maximum height, the velocity and acceleration vectors are perpendicular to each other.

Explanation: At the maximum height the ball stops going up and starts going down. Then, there is a given time at with the velocity of the ball (in the y-axis) is equal to zero.

And as you may know, every lifted object is pulled down by the gravitational force, thie means that the ball is accelerated when it is in the air, so the acceleration is not zero at the maximum height.

Here remember that the player kicked the ball in a given direction, so the ball has a compoent of velocity in the y-axis (that is zero at the point of maximum height) and a component in the x-axis.

Then, at maximum height the velocity is only in the x-direction, and the acceleration is pointing down (in the negative y-direction) so at this point the acceleration and the velocity are perpendiculars.

Stels [109]3 years ago
3 0

At position of maximum height we know that the vertical component of its velocity will become zero

so the object will have only horizontal component of velocity

so at that instant the motion of object is along x direction

while if we check the acceleration of object then it is due to gravity

so the acceleration of object is vertically downwards

so it is along y axis

so here these two physical quantities are perpendicular to each other

so correct answer would be

<em>C)At the maximum height, the velocity and acceleration vectors are perpendicular to each other. </em>

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A mechanical wave can only travel through matter.

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3 years ago
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A frame hanging on a wall is held by two cables. The tension in each cable is 30 N, and the cables make an angle of 45° with the
Dimas [21]

Answer: option D) 42.4 N

The weight of the frame is balanced by the vertical component of tension.

W = T sin θ + T sin θ = 2 T sin θ

The tension in each cable is T = 30 N

Angle made by the cables with the horizontal, θ = 45°

⇒ W = 2×30 N × sin 45° = 2 × 30 N × 0.707 = 42.4 N

Hence, the weight of the frame is 42.4 N. Correct option is D.


6 0
3 years ago
For a vehicle to negotiate a banked curve in poor weather conditions, where the force of friction f = 0, for a given velocity v
djverab [1.8K]

Answer:

R=240m

Explanation:

From the question we are told that:

Velocity v=25m/s

Force of friction f = 0

Angle \theta=15

Generally the equation for  Radius of curvature is mathematically given by

R=frac{v^2}{tan\theta *g}

R=frac{25^2}{tan 15 *9.81}

R=240m

7 0
3 years ago
Select the correct answer from each drop-down menu. A device that uses electricity and magnetism to create motion is called a __
Fittoniya [83]
<h3><u>Answer;</u></h3>

1st drop; Motor

2nd drop; Electricity

A device that uses electricity and magnetism to create motion is called a <u>motor</u>. In a reverse process, a device that uses motion and magnesium can be used to create <u>electricity</u>.

<h3><u>Explanation</u>;</h3>
  • <em><u>Motors are device which use electricity and magnetism to create motion.</u></em> They pass alternating current through opposing pairs of magnets to create a rotating magnetic field which creates a magnetic field in the rotor of a motor, making it to spin around.
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5 0
3 years ago
You are standing in a building whose height (40m) you throw a ball downward at a angle of -30 at a speed of (10m/s) acceleration
jeyben [28]

Answer: 3.41 s

Explanation:

Assuming the question is to find the time t the ball is in air, we can use the following equation:

y=y_{o}+V_{o}sin \theta t-\frac{1}{2}gt^{2}

Where:

y=0m is the final height of the ball

y_{o}=40 m is the initial height of the ball

V_{o}=10 m/s is the initial velocity of the ball

t is the time the ball is in air

g=9.8 m/s^{2} is the acceleration due to gravity  

\theta=30\°

Then:

0 m=40 m+(10 m/s)(sin(30\°))t-\frac{1}{2}9.8 m/s^{2}t^{2}

0 m=40 m+5m/s t-4.9 m/s^{2}t^{2}

Multiplying both sides of the equation by -1 and rearranging:

4.9 m/s^{2}t^{2}-5m/s t-40 m=0

At this point we have a quadratic equation of the form at^{2}+bt+c=0, which can be solved with the following formula:

t=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a}

Where:

a=4.9

b=-5

c=-40

Substituting the known values:

t=\frac{-(-5) \pm \sqrt{(-5)^{2}-4(4.9)(-40)}}{2(4.9)}

Solving the equation and choosing the positive result we have:

t=3.41 s  This is the time the ball is in air

5 0
4 years ago
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