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kaheart [24]
4 years ago
7

A box contains 3 plain pencils and 9 plain pens. A second box contains 7 color pencils and 3 crayons. One item from the box is c

hosen at random. What is the probability that a plain pencil from the first box and a color pencil from the second box are selected?
Mathematics
1 answer:
user100 [1]4 years ago
5 0

Answer:

Box A contains =3pain pencils and 9 plain pens

Box B contains 7color pencils and 3 crayons

probablilty=event space/sample space or number of outcome/total no.of possible outcome

probability that a plain pencil from the first box will be selected =3/11

probability that a color pencil from the second box will be selected=7/10

therefore probability that a plain pencil from the first box and a color pencil from second box will be selected=3/11 plus 7/10=110/110=1.

therefore the answer is 1.

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Answer:

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Step-by-step explanation:

Perhaps the easiest way to evaluate this numerical expression is to let a calculator do it. Alternatively, we can compute the value from a +1/a.

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<h3>expression</h3>

Consider the square of a +1/a:

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This means ...

  a^2 +1/a^2 = (a +1/a)^2 -2

Similarly, using a^2 for 'a' in the above, we have ...

  a^4 +1/a^4 = (a^2 +1/a^2)^2 -2

<h3>numerical value</h3>

The value of a +1/a is ...

  a+\dfrac{1}{a}=3-2\sqrt{2}+\dfrac{1}{3-2\sqrt{2}}=(3-2\sqrt{2})+\dfrac{3+2\sqrt{2}}{3^2-(2\sqrt{2})^2}\\\\=(3-2\sqrt{2})+(3+2\sqrt{2})\\\\a+\dfrac{1}{a}=6

Then the value of a^2 +1/a^2 is 6^2 -2 = 34

and the value of a^4 +1/a^4 is 34^2 -2 = 1154

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As per the statement:

Anderson uses the discriminant to correctly find the number of real solutions of the quadratic equation:

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