Answer:
The domain of the function should be:
'x greater than or equal to negative -5'.
Hence, option A is true.
Step-by-step explanation:
Given the expression

The domain of a function is the set of input or arguments for which the function is real and defined
We know that the value, inside the radicand, is the number found inside a radical symbol which must be greater than 0, otherwise, it would make the function undefined,
i.e.
x-5 ≥ 0
x ≥ 5
In other words, the domain of the function should be:
'x greater than or equal to negative -5'.
Therefore, the domain of the function:
x ≥ 5

Hence, option A is true.
complette the square to get vertex form or y=a(x-h)^2+k
(h,k) is vertex
1. group x terms, so for y=ax^2+bx+c, do y=(ax^2+bx)+c
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2, factor out the leading coefinet (constant in front of the x^2 term), basicallly factor out a
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3. take 1/2 of the linear coefient (number in
front of the x), and square it ,then add negative and positive of it
inside parnthases
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4. complete the squre and expand
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so
y=-1/4x^2+4x-19
group
y=(-1/4x^2+4x)-19
undistribute -1/4
y=-1/4(x^2-16x)-19
take 1/2 of -16 and squer it to get 64 then add neg and pos inside
y=-1/4(x^2-16x+64-64)-19
factorperfect square
y=-1/4((x-8)^2-64)-19
expand
y=-1/4(x-8)^2+16-19
y=-1/4(x-8)^2-3
vertex is (8,-3)
Assume the following:
Brad has been in the soccer team for b years.
Scot has been in the soccer team for s years.
"The number of years that brad has been on the soccer team is 2 less than 5 times the number of years that Scott has"
means: b=5s-2
"in total,the boys have been on the soccer team for 10 years."
means: b+s=10
so we have the equations:
i) b=5s-2
ii) b+s=10
substitute b in ii) with 5s-2, as they are equal, from i
(5s-2)+s=10
5s-2+s=10
6s=12
s=2,
then , from b+s=10, b=8
Answer: Brad has been in the team for 8 years.
The answer is 5.19615242271 but if you round it to the nearest dp its 5.2