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kozerog [31]
3 years ago
12

Find the algebraic representation of the reflection below.

Mathematics
2 answers:
Natali [406]3 years ago
8 0

Answer:

The correct answer is B ( x, -y )

Step-by-step explanation:

bogdanovich [222]3 years ago
7 0
I really don’t know the answer but good luck bro
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Let R be the relation on the set of ordered pairs of positive integers such that ((a, b), (c, d)) ∈ R if and only if ad = bc. Ar
Veseljchak [2.6K]

Answer:

The given relation R is equivalence relation.

Step-by-step explanation:

Given that:

((a, b), (c, d))\in R

Where R is the relation on the set of ordered pairs of positive integers.

To prove, a relation R to be equivalence relation we need to prove that the relation is reflexive, symmetric and transitive.

1. First of all, let us check reflexive property:

Reflexive property means:

\forall a \in A \Rightarrow (a,a) \in R

Here we need to prove:

\forall (a, b) \in A \Rightarrow ((a,b), (a,b)) \in R

As per the given relation:

((a,b), (a,b) ) \Rightarrow ab =ab which is true.

\therefore R is reflexive.

2. Now, let us check symmetric property:

Symmetric property means:

\forall \{a,b\} \in A\ if\ (a,b) \in R \Rightarrow (b,a) \in R

Here we need to prove:

\forall {(a, b),(c,d)} \in A \ if\ ((a,b),(c,d)) \in R \Rightarrow ((c,d),(a,b)) \in R

As per the given relation:

((a,b),(c,d)) \in R means ad = bc

((c,d),(a,b)) \in R means cb = da\ or\ ad =bc

Hence true.

\therefore R is symmetric.

3. R to be transitive, we need to prove:

if ((a,b),(c,d)),((c,d),(e,f)) \in R \Rightarrow ((a,b),(e,f)) \in R

((a,b),(c,d)) \in R means ad = cb.... (1)

((c,d), (e,f)) \in R means fc = ed ...... (2)

To prove:

To be ((a,b), (e,f)) \in R we need to prove: fa = be

Multiply (1) with (2):

adcf = bcde\\\Rightarrow fa = be

So, R is transitive as well.

Hence proved that R is an equivalence relation.

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