Mia is working two summer jobs, making $11 per hour babysitting and making $20 per hour lifeguarding. In a given week, she can w
2 answers:
9514 1404 393
Answer:
- x + y ≤ 15
- 11x +20y ≥ 220
- 3 hours babysitting and 11 hours lifeguarding
Step-by-step explanation:
The two inequalities represent the two relations described in the problem statement.
x + y ≤ 15 . . . . . . . Mia works a maximum of 15 hours
11x + 20y ≥ 220 . . . . Mia makes at least $220
These are graphed in the attachment. The solution area is the doubly-shaded area with vertices at (9, 6), (0, 11) and (0, 15). One possible solution is shown at (3, 11), which represents ...
3 hours babysitting
11 hours lifeguarding . . . . . . . . total 14 hours for $253
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Answer: |p-72% |≤ 4%
Step-by-step explanation:
Let p be the population proportion.
The absolute inequality about p using an absolute value inequality.:
, where E = margin of error,
= sample proportion
Given: A poll result of 72% with a margin of error of 4% indicates that p is most likely to be between 68% and 76% .
|p-72% |≤ 4%
⇒ 72% - 4% ≤ p ≤ 72% +4%
⇒ 68% ≤ p ≤ 76%.
i.e. p is most likely to be between 68% and 76% (.