Question

1.674 x 10^–24 g of neutrons is how many atomic mass units (amu)?

Answer 1

Answer : The atomic mass in $1.674\times 10^{-24}g$ of neutrons are, 1.008 amu.

Explanation :

1 mole of substance always contains $6.022\times 10^{23}$ number of atoms. The mass of one moles of any substance is equal to the atomic mass unit.

As we know that,

1 gram = $6.022\times 10^{23}amu$

As we are given that:

Mass of neutrons = $1.674\times 10^{-24}g$

Now we have to determine the number of atomic mass unit.

As, 1 gram = $6.022\times 10^{23}amu$

So, $1.674\times 10^{-24}g$ = $\frac{1.674\times 10^{-24}g}{1g}\times (6.022\times 10^{23}amu)$

                         = 1.008 amu

Therefore, the atomic mass in $1.674\times 10^{-24}g$ of neutrons are, 1.008 amu.

Answer 2

Atomic mass units is a unit of measurement of mass, same with grams. Therefore, we can convert the two measurements back and forth using a conversion factor. For every 1 amu, there are 1.66054×10⁻²⁴ grams. The solution is as follows:

(1.674×10⁻²⁴ g)(1 amu/1.66054×10⁻²⁴ g) = 1.008 amu of neutrons