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2 years ago

2C₂H6 + 702 —>4C02 + 6H₂O

Chemistry

1 answer:

navik [9.2K]2 years ago

8 0

Answer:

975.56×10²³ molecules

Explanation:

Given data:

Number of molecules of C₂H₆ = 4.88×10²⁵

Number of molecules of CO₂ produced = ?

Solution:

Chemical equation:

2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O

Number of moles of C₂H₆:

1 mole = 6.022×10²³ molecules

4.88×10²⁵ molecules×1mol/6.022×10²³ molecules

0.81×10² mol

81 mol

Now we will compare the moles of C₂H₆ with CO₂.

C₂H₆ : CO₂

2 : 4

81 : 4/2×81 = 162 mol

Number of molecules of CO₂:

1 mole = 6.022×10²³ molecules

162 mol ×6.022×10²³ molecules / 1 mol

975.56×10²³ molecules

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15.0 mL of an unknown clear liquid is added to a 50 mL graduated cylinder. The mass of the liquid is determined to be 12.7 grams

sveticcg [70]

Answer:

$\boxed {\tt A. \ d=0.85 \ g/mL}$

Explanation:

Density is found by dividing the mass by the volume.

$d=\frac{m}{v}$

The mass of the liquid is 12.7 grams.

We know that 15 mL of this liquid was added to a 50 mL graduated cylinder. Therefore, the volume is 15 mL. The 50 mL is not relevant, it only tells us about the graduated cylinder.

$m= 12.7 \ g\\v= 15 \ mL$

Substitute the values into the formula.

$d=\frac{12.7 \ g}{ 15 mL}$

Divide.

$d=0.846666667 \ g/mL$

Round to the nearest hundredth. The 6 in the tenth place tells us to round the 4 to a 5.

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The density of the liquid is about 0.85 grams per milliliter and choice A is correct.

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2 years ago

How many grams of iron oxide, Fe2O3 will be produced if 165 g of O2 gas is supplied? (follow the same steps as mol to mol, only

forsale [732]

Answer:

$m_{Fe_2O_3}=549gFe_2O_3$

Explanation:

Hello there!

In this case, according to the given chemical reaction for this problem about stoichiometry:

$4Fe+3O_2\rightarrow 2Fe_2O_3$

Whereas there is a 3:2 mole ratio of oxygen (molar mass = 32.0 g/mol) to iron (III) oxide (molar mass = 159.69 g/mol) and therefore, the correct stoichiometric setup is:

$m_{Fe_2O_3}=165gO_2*\frac{1molO_2}{32.00gO_2}*\frac{2molFe_2O_3}{3molO_2} *\frac{159.69gFe_2O_3}{1molFe_2O_3} \\\\m_{Fe_2O_3}=549gFe_2O_3$

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2 years ago

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Sholpan [36]

Answer:

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Explanation:

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2 years ago

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Automobile catalytic Converters use a platinum callus to reduce air pollution by changing emissions such as carbon monoxide CO2

natka813 [3]

Answer:

14 mol O₂

Explanation:

The reaction between CO and O₂ is the following:

CO + O₂ → CO₂

We balance the equation with a coefficient 2 in CO and CO₂ to obtain the same number of O atoms:

2CO + O₂ → 2CO₂

As we can see from the balanced equation, 1 mol of O₂ is required to react with 2 moles of CO. Thus, the conversion factor is 1 mol of O₂/2 mol CO. We multiply the moles of CO by the conversion factor to calculate the moles of O₂ that are required:

28 mol CO x 1 mol of O₂/2 mol CO = 14 mol O₂

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1 year ago