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DerKrebs [107]
3 years ago
8

A vineyard owner is planting several new rows of grapevines, and needs to know how many grapevines to plant in each row. She has

determined that after measuring the length of a future row, she can use the following formula to calculate the number of vines that will be in the row, along with the trellis end-post assemblies that will need to be constructed at each end of the row: R-2E The terms in the formula are o V is the number of grapevines that will fit in the row. A131 Programming Assignment ·R is the length of the row, in feet E is the amount of space, in feet, used by an end-post assembly . S is the space between vines, in feet. Write a program that makes the calculation for the vineyard owner. The progranm should ask the user to input the following » The length of the row, in feet . The amount of space used by an end-post assembly, in feet . The amount of space between vines, in feet Once the input data has been entered, the program should calculate and display the number of (whole) grapevines that will fit in the row. Enter the length of the row (in feet): 20 Enter the length of the end-post (in feet): 4 Enter how much space between vines (in feet): 2 You can plant 6 vines
Engineering
1 answer:
boyakko [2]3 years ago
8 0

Answer:

Finally, display the number of grapevines that will fit in the row

Explanation:

A vineyard owner is planting several new rows of grapevines, and needs to know how many grapevines to plant in each row. She has determined that after measuring the length of a future row, she can use the following formula to calculate the number of vines that will fit in the row, along with the trellis end-post assemblies that will need to be constructed at each end of the row:

V=R-2E/S

The terms in the formula are:

V is the number of grapevines that will fit in the row.

R is the length of the row, in feet.

E is the amount of space, in feet, used by an end-post assembly.

S is the space between vines, in feet.

Write a program that makes the calculation for the vineyard owner. The program should ask the user to input the following:

• The length of the row, in feet

• The amount of space used by an end-post assembly, in feet

• The amount of space between the vines, in feet

Once the input data has been entered, the program should calculate and display the number of grapevines that will fit in the row.

• Declare the variables amountSpace, vinesSpace, and grapevines of double type.

• Prompt and read the length of the row, in feet, the amount of space, in feet, and the space between vines, in feet.

• Calculate the number of grapevines that will fit in the row using the below formula:

grapvines=(rowLength-2*amountSpace)/vinesSpace;

• Finally, display the number of grapevines that will fit in the row.

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zalisa [80]

Answer:

The total load carried by the fiber will be "98%".

Explanation:

The given values are:

V_{f}=0.61

V_{m}=1-V_{f}

     =1-0.61

     =0.39

E_{f}=10 \ Mpa

\sigma_{f}=0.35 \ Mpa

E_{m}=0.45 \ Mpa , \sigma_{m}=9\times 10^{-3} \ Mpa

As we know,

⇒  E_{e}=fE_{f}+mE_{m}

On putting the estimated values, we get

⇒       =0.61\times 10+0.39\times 0.95

⇒       =6.27 \ Mpa

Now,

⇒  \sigma_{c}=f\sigma_{f}+m\sigma_{m}

On putting the estimated values, we get

⇒       =0.61\times 0.35+0.39\times 0.009

⇒       =0.217 \ Mpa

Therefore,

The load carried by fiber,

=\frac{f\sigma_{f}}{\sigma_{c}}

=\frac{0.35\times 0.61}{0.217}

=0.98 i.e., 98%

4 0
4 years ago
Need help with these 3 questions pls help
Burka [1]

Answer:

Explanation:

First one is passion i think

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3 years ago
Consider two different types of motors. Motor A has a characteristic life of 4100 hours (based on a MTTF of 4650 hours) and a sh
Daniel [21]

Answer:B

Explanation:

Given

For motor A

Characteristic life(r)=4100 hr

MTTF=4650 hrs

shape factor(B )=0.8

For motor B

Characteristic life(r)=336 hr

MTTF=300 hr

Shape Factor (B)=3

Reliability for 100 hours

R_a=e^{-\left ( \frac{T-r}{n}\right )B}

R_a=e^{-\left ( \frac{4650-4100}{100}\right )0.8}

R_a=e^{-4.4}=0.01227

For B

R_b=e^{-\left ( \frac{300-336}{100}\right )3}

R_b=e^{1.08}=2.944

B is better for 100 hours

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R_a=e^{-0.5866}=0.55621

R_b=e^{0.144}=1.154

So here B is more Reliable.

3 0
3 years ago
Explain how use of EGR is effective in reducing NOx emissions 4. In most locations throughout the U.S., the octane number of reg
TiliK225 [7]

Answer:please see attached file

Explanation:

3 0
4 years ago
I am making composites of silicone rubber and copper particles; by mixing thermally conductive particles into the thermally insu
Gelneren [198K]

Answer:

The composition of Composite of Volume basis is 2.154% Copper and 97.83% Rubber.

Explanation:

Let us assume that the total mass of composite is 100 lbm So as per the given conditions

  • 15 lbm is copper and 85 lbm is rubber.
  • Density of rubber is 70 lbm/ft3
  • Specific gravity of Copper is 9

So As per the formula of specific gravity

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here density of water is 62.4 lbm/ft3

Solving for Density of Copper gives

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For composition on volume basis, volume of individual components and composite are calculated as

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The composition is given as

c_{cu}=\frac{V_{cu}}{V_{c}}\\c_{cu}=\frac{0.0267}{1.2409} \times 100 \%\\c_{cu}=2.154 \%\\\\c_{r}=\frac{V_{r}}{V_{c}}\\c_{r}=\frac{1.214}{1.2409} \times 100 \%\\c_{r}=97.83 \%

So the composition of Composite of Volume basis is 2.154% Copper and 97.83% Rubber.

6 0
3 years ago
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