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2 years ago

A resistivity meter is measured in

Engineering

2 answers:

timama [110]2 years ago

4 0

Answer:

Ohm meter

Explanation:

A resistivity meter is measured in Ohm meter.

Hope it is helpful to you

Bingel [31]2 years ago

3 0

Ohms ..................

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What is brainstorming and why is it important to create the perfect solution to a problem? giving brainliest to the first answer

Diano4ka-milaya [45]

Brainstorming allows people to think freely without judge, or fear to share there answer. Basically encourages people to open up to what they believe.

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2 years ago

section 10.1 describes a man in the middle attack on the diffie-hellman key exhange protocal in which the adversary generates tw

nika2105 [10]

Answer:

1. James will attack by generating a random private key XD and a corresponding public key YD.

2. Jane transmit YA to another person called Alex.

3. James intercept YA and transmit YD to jane.

4. Jane receive YD and calculate K1

At this point james and jane thinks they share a secret key but instead james has a secret key k1 to Jane and k2 to alex.

5. Alex transmit another key XA to alex for example.

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3 years ago

A coil with an average diameter of 5 inch will have an area of ""blank"" square meters

nadezda [96]

Answer:

19.64 square inches

Explanation:

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2 years ago

Type the correct answer in the box. Spell all words correctly.

Otrada [13]

Answer:

solar engineering field

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3 years ago

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A cylindrical resistor element on a circuit board dissipates 0.6 W of power. The resistor is 1.5 cm long, and has a diameter of

Burka [1]

Answer:

a. 51.84Kj

b. 2808.99 W/m^2

c. 11.75%

Explanation:

Amount of heat this resistor dissipates during a 24-hour period

= amount of power dissipated * time

= 0.6 * 24 = 14.4 Watt hour

(Note 3.6Watt hour = 1Kj )

=14.4*3.6 = 51.84Kj

Heat flux = amount of power dissipated/ surface area

surface area = area of the two circular end + area of the curve surface

$=2*\frac{\pi D^{2} }{4} + \pi DL\\=2*\frac{\pi *(\frac{0.4}{100} )^{2} }{4} + \pi *\frac{0.4}{100} *\frac{1.5}{100}$

= 2.136 *10^-4 $m^{2}$

Heat flux = $\frac{0.6}{2.136 * 10^{-4} }$ = 2808.99 $W/m^{2}$

fraction of heat dissipated from the top and bottom surface

$=\frac{\frac{2*\pi D^{2} }{4} }{\frac{2*\pi D^{2}}{4} + \pi DL } \\\\=\\\frac{\frac{2*\pi *(\frac{0.4}{100} )^{2} }{4} }{\frac{2*\pi *(\frac{0.4}{100} )^{2} }{4} +\pi *\frac{0.4}{100} *\frac{1.5}{100} } \\\\=\frac{2.51*10^{-5} }{2.136*10^{-4} } \\\\\= 0.1175$

=11.75%

8 0

3 years ago

Read 2 more answers