Answer:
Step 1
Elevate the front of the vehicle using the floor jack and support the vehicle with two jack stands. Make sure the vehicle is stable.
Step 2
Disengage all electrical components connected to the transmission. Indicate by marking the position of the drive shaft for its reinstallation. From the output shaft, remove the rear U joint. Jam the cloth to keep the liquid from dripping out of the extension housing.
Step 3
Loosen the shift linkages and the speedometer cable from the transmission manually. Place the transmission jack under the transmission, and then take a socket wrench and remove the support nut, the cross-member, and the rear support insulator from the rear engine. Support the engine with a jack stand and use the transmission jack to withdraw the transmission toward the rear of the vehicle.
Explanation:
Uhm is there a multiple choice?
Answer:
Both Technicians A and B are correct
Explanation:
If the fluid pressure will decrease quickly in a car when the ignition says that one or more has been switched off. One or two could be leaking or the source could be a faulty check mechanism in the catalytic converter.
If the diameter of the bar is 0.490 at this load, determine I. the engineering stress and strain, and [2] II. the true stress and strain is 1561. 84 MPa.
<h3>What is strain?</h3>
Strain is a unitless degree of ways a great deal an item receives larger or smaller from an implemented load. Normal stress happens while the elongation of an item is in reaction to an everyday pressure (i.e. perpendicular to a surface), and is denoted via way of means of the Greek letter epsilon.
- L = 20 cm d x 1 = 0.21 cm
- dx 2 = 0.25 cmF=5500 a) σ= F/A1= 5000/(π/4x(0.0025)^2)= 1018.5916 MPa lateral stress= Ad/d1= (0.0021-0.0025)/0.0025 = - 0.1 longitudinal stress (ɛ_l)= -lateral stress/v = -(-0.16)/0.3
- (assuming a poisson's ration of 0.3) ε_l=0.16/0.3 = 0.5333
- b) σ_true= σ(1+ ɛ_I)= 1018.5916(1+0.5333
- = 1561.84 MPa.
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Answer:
The strain is 0.0947.
Explanation:
Strain is the ration of change in dimension to the original dimension under application of load. Depending upon load, the bar may stretch or compress. So, the strain can be negative in case of compression or positive in case of tension.
Step1
Given:
Original length of the steel bar is 0.66 ft or 7.92 in.
Stretch in the bar is of 0.75 in.
Calculation:
Step2
Strain is calculated as follows:
e = 0.0947
Positive sign is for stretching condition of the bar.
Thus, the strain is 0.0947.
