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Sedbober [7]
3 years ago
5

Explain how use of EGR is effective in reducing NOx emissions 4. In most locations throughout the U.S., the octane number of reg

ular grade gasoline [defined as (R+M)/2] is 87. However, in certain high elevation locations (parts of CO, ID, MT, UT, and WY) regular gasoline may have a lower octane value of 85. Explain how a lower octane fuel can be used in these areas without it leading to unacceptable knocking
Engineering
1 answer:
TiliK225 [7]3 years ago
3 0

Answer:please see attached file

Explanation:

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Which of the following is used in the electrical field?
weeeeeb [17]

Answer:

pliers

Explanation:

because that makes the most sense

6 0
3 years ago
Write a program that prompts for a line of text and then transforms the text based on chosen actions. Actions include reversing
nlexa [21]

Answer:

public class TextConverterDemo

{

//Method definition of action1337

public static String action1337(String current)

{

//Replace each L or l with a 1 (numeral one)

 current = current.replace('L', '1');

 current = current.replace('l', '1');

 

 //Replace each E or e with a 3 (numeral three)

 current = current.replace('E', '3');

 current = current.replace('e', '3');

 //Replace each T or t with a 7 (numeral seven)

 current = current.replace('T', '7');

 current = current.replace('t', '7');

 //Replace each O or o with a 0 (numeral zero)

 current = current.replace('O', '0');

 current = current.replace('o', '0');

 

//Replace each S or s with a $ (dollar sign)

 current = current.replace('S', '$');

 current = current.replace('s', '$');

 return current;

}

//Method definition of actionReverse

//This method is used to reverses the order of

//characters in the current string

public static String actionReverse(String current)

{

 //Create a StringBuilder's object

 StringBuilder originalStr = new StringBuilder();

 //Append the original string to the StribgBuilder's object

 originalStr.append(current);

 //Use reverse method to reverse the original string

 originalStr = originalStr.reverse();

 

 //return the string in reversed order

 return originalStr.toString();

}

//Method definition of main

public static void main(String[] args)

{

    //Declare variables

 String input, action;

 

 //Prompt the input message

 System.out.println("Welcome to the Text Converter.");

 System.out.println("Available Actions:");

 System.out.println("\t1337) convert to 1337-speak");

 System.out.println("\trev) reverse the string");

 System.out.print("Please enter a string: ");

   

 //Create a Scanner class's object

 Scanner scn = new Scanner(System.in);

 

 //Read input from the user

 input = scn.nextLine();

 do

 {

  /*Based on the action the user chooses, call the appropriate

   * action method. If an unrecognized action is entered then

   * the message "Unrecognized action." should be shown on a

   * line by itself and then the user is prompted again just

   * as they were when an action was performed.

   * */

  System.out.print("Action (1337, rev, quit): ");

  action = scn.nextLine();

  if (action.equals("1337"))

  {

   input = action1337(input);

   System.out.println(input);

  } else if (action.equals("rev"))

  {

   input = actionReverse(input);

   System.out.println(input);

  } else if (!action.equals("quit"))

  {

   System.out.println("Unrecognized action.");

  }

 } while (!action.equals("quit"));

 System.out.println("See you next time!");

 scn.close();

}

}

7 0
3 years ago
W10L1-Show It: Pythagorean Theorem<br> Calculate the total material in the picture.<br> 4<br> 3
Fantom [35]

Answer:

35

Explanation: I really dont even know, I just used up all my tries on it and got it wrong on every other thing i chose. So it's 35 i believe cause its the only answer i didnt choose.

7 0
3 years ago
A binary geothermal power plant uses geothermal water at 160°C as the heat source. The cycle operates on the simple Rankine cycl
bogdanovich [222]

A binary geothermal power operates on the simple Rankine cycle with isobutane as the working fluid. The isentropic efficiency of the turbine, the net power output, and the thermal efficiency of the cycle are to be determined

Assumptions :

1.  Steady operating conditions exist.

2.  Kinetic and potential energy changes are negligible.

Properties:  The specific heat of geothermal water ( c_{geo}[) is taken to be 4.18 kJ/kg.ºC.  

Analysis (a) We need properties of isobutane, we can obtain the properties from EES.

a. Turbine

PP_{3} = 3.25mPa = (3.25*1000) kPa\\= 3250kPa\\from the EES TABLE\\h_{3} = 761.54 kJ/kg\\s_{3} = 2.5457 kJ/kg\\P_{4} = 410kPa\\\\s_{4} = s_{3} \\h_{4s} = 470.40kJ/kg\\\\T_{4} = 179.5^{0} C\\\\h_{4} = 689.74 kJ/KG\\\\ The  isentropic  efficiency, n_{T} = \frac{h_{3}-h_{4}  }{h_{3}- h_{4s} }

==\frac{761.54-689.74}{761.54-670.40} \\=\frac{71.8}{91.14} \\=0.788

b. Pump

h_{1} = h_{f} @ 410kPa = 273.01kJ/kg\\v_{1} = v_{f} @ 410kPa = 0.001842 m^{3}/kgw_{p,in} =  \frac{v_{1}(P_{2}-P_{1})   }{n_{p} } \\\\= \frac{0.01842(3250-410)}{0.9} \\\\ =5.81kJ/kg\\h_{2} =h_{1} + w_{p,in}\\          = 273.01+5.81\\           = 278.82 kJ/kg\\\\w_{T,out} = m^{.}  (h_{3} -h_{4} )\\=(305.6)(761.54-689.74)\\=305.6(71.8)\\=21,942kW\\\\

W^{.} _ {P,in} = m^{.} (h_{2} -h_{1}) \\=m^{.}  w_{p,in \\=305.6(5.81)\\\\=1,777kW\\W^{.}  _{net} = W^{.} _{T, out} - W^{.}  _{P,in} \\= 21,942-1,777\\=20,166 kW\\\\HEAT EXCHANGER\\\\Q_{in} = m^{.} _{geo} c_{geo} (T_{in-T_{out} } )\\=555.9(4.18)(160-90)\\=162.656kW\\

c. The thermal efficiency of the cycle  n_{th}  =\frac{W^{.} _{net} }{Q^{._{in} } } \\\\= \frac{20,166}{162,656} \\=0.124\\=12.4%

7 0
3 years ago
Read 2 more answers
Consider two Carnot heat engines operating in series. The first engine receives heat from the reservoir at 1400 K and rejects th
Aleksandr-060686 [28]

Answer:

The temperature T= 648.07k

Explanation:

T1=input temperature of the first heat engine =1400k

T=output temperature of the first heat engine and input temperature of the second heat engine= unknown

T3=output temperature of the second heat engine=300k

but carnot efficiency of heat engine =1 - \frac{Tl}{Th} \\

where Th =temperature at which the heat enters the engine

Tl is the  temperature of the environment

since both engines have the same thermal capacities <em>n_{th} </em> therefore n_{th} =n_{th1} =n_{th2}\\n_{th }=1-\frac{T1}{T}=1-\frac{T}{T3}\\ \\= 1-\frac{1400}{T}=1-\frac{T}{300}\\

We have now that

\frac{-1400}{T}+\frac{T}{300}=0\\

multiplying through by T

-1400 + \frac{T^{2} }{300}=0\\

multiplying through by 300

-420000+ T^{2} =0\\T^2 =420000\\\sqrt{T2}=\sqrt{420000}  \\T=648.07k

The temperature T= 648.07k

5 0
3 years ago
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