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3 years ago

Change 5 2/3 to a improper fraction.Show you're work

Mathematics

2 answers:

Pachacha [2.7K]3 years ago

5 0

5 2/3 is equal to 17/3. the denominator 3 stays the same. u do 3 times 5+2 to get the numerator

Vesna [10]3 years ago

5 0

You multiply 5 by 3 and add 2. Basically multiply the integer by the denominator and add the numerator.

Hope this helps!

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This also please and thank you for those who do decide to help me

alex41 [277]

240 for # 2 because 6 times 4 times 10 is equal to 240

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4 years ago

Factorization of the expression (3x-2y)((a+b)+(4x-3y)(a+b)

Mrrafil [7]

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3 years ago

The number of cars sold per month can be modeled by f(x) = 0.04x^3 + 0.2x^2 + 0.5x + 60, where x represents the number of months

Karolina [17]

Answer:

0.04x^3+0.2x^2+0.5x+90 vertical shift 30 units up, increase of 30 units per month

Step-by-step explanation:

You don't need an explanation just take the answer.

6 0

3 years ago

Point G is the centroid of the right △ABC with m∠C=90° and m∠B=30°. Find AG if CG=4 ft.

o-na [289]

Answer: $\text{Length of AG=}\frac{2\sqrt{63}}{3}$

Explanation:

Please follow the diagram in attachment.

As we know median from vertex C to hypotenuse is CM

$\therefore CM=\frac{1}{2}AB$

We are given length of CG=4

Median divide by centroid 2:1

CG:GM=2:1

Where, CG=4

$\therefore GM=2$ ft

Length of CM=4+2= 6 ft

$\therefore CM=\frac{1}{2}AB\Rightarrow AB=12$

In $\triangle ABC, \angle C=90^0$

Using trigonometry ratio identities

$AC=AB\sin 30^0\Rightarrow AC=6$ ft

$BC=AB\cos 30^0\Rightarrow BC=6\sqrt{3}$ ft

$CN=\frac{1}{2}BC\Rightarrow CN=3\sqrt{3}$ ft

In $\triangle CAN, \angle C=90^0$

Using pythagoreous theorem

$AN=\sqrt{6^2+(3\sqrt{3})^2\Rightarrow \sqrt{63}$

Length of AG=2/3 AN

$\text{Length of AG=}\frac{2\sqrt{63}}{3}$ ft

5 0

3 years ago

Factor the polynomial completely 6x^2-3x+2

fenix001 [56]

Answer:

can't be factored

answer is D

7 0

3 years ago

Read 2 more answers