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2 years ago

How do I write 56 1/4% as a fraction in simplest form

2 answers:

4 0

The answer is 9/16 because 56 1/4% = 56.25% and any percent is out of 100 so into a fraction it's 56.25/100. Because it's now a decimal over a fraction you divide 56.25 by 100 to get .5625 but every number is over 1 so now you have .5625/1 now that you have this fraction you have to make the decimal whole so you would multiply .5625/1 by 10000/10000 and get 5625/10000. You simplify 5625/10000 and get 9/16.

meriva2 years ago

3 0

56 1/4% = 9/16
Hope this helps!

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What are the solutions to the equations |x-10|-4=2x

Tamiku [17]

X is going to equal two in this equation.

7 0

2 years ago

Solve for X:<br> x/5 + 4 = 6

STALIN [3.7K]

Answer:10

Step-by-step explanation:

X/5+4 = 6

(Subtract 4 on both sides)

X/5 =2

(Multiply 5 on both sides to get x alone)

2(5) = 10

X = 10

3 0

2 years ago

Read 2 more answers

An arithmetic sequence has this recursive formula: (a^1 =8, a^n= a^n-1 -6

eduard

Answer:

$a_n = 8 + (n - 1) (-6)$

Step-by-step explanation:

Given

$a_1 = 8$

Recursive: $a_{n} = a_{n-1} - 6$

Required

Determine the formula

Substitute 2 for n to determine $a_2$

$a_{2} = a_{2-1} - 6$

$a_{2} = a_{1} - 6$

Substitute $a_1 = 8$

$a_2 = 8 - 6$

$a_2 = 2$

Next is to determine the common difference, d;

$d = a_2 - a_1$

$d = 2 - 8$

$d = -6$

The nth term of an arithmetic sequence is calculated as

$a_n = a_1 + (n - 1)d$

Substitute $a_1 = 8$ and $d = -6$

$a_n = a_1 + (n - 1)d$

$a_n = 8 + (n - 1) (-6)$

Hence, the nth term of the sequence can be calculated using $a_n = 8 + (n - 1) (-6)$

3 0

3 years ago

Mandy cut 34 1⁄3 feet of string to use for the tail of a kite. However, she realized that the tail was too long and cut off 6 3⁄

andrezito [222]

34 1/3- 6 3/5= 416/15

8 0

3 years ago

The lines 2x=ky+2 and (k+1)x=6y-3 have same gradient. Find possible values of k

faust18 [17]

Answer:

k = 3 or k = -4

(Anyone can correct me if I'm wrong)

Step-by-step explanation:

$2x=ky+2\to\ eq1\\(k+1)x=6y-3\to\ eq2\\$Change to this form: $y=mx+c\\ky=2x-2\\y=\frac{2x-2}{k}\\$gradient of eq1: $\frac{2}{k}\\6y=(k+1)x+3\\y=\frac{(k+1)x+3}{6}\\y=\frac{k+1}{6} x+\frac{3}{6}\\y= \frac{k+1}{6} x+\frac{1}{2}\\$gradient of eq1: $\frac{k+1}{6}\\$Since gradient, m, is the same for both lines,$\\\frac{2}{k}=\frac{k+1}{6}\\12=k^{2}+k\\k^{2}+k-12=0\\(k-3)(k+4)=0\\k=3 $ or $ k=-4$

6 0

2 years ago