SinA= opposite/hypotenuse
sinA= 12/13
Answer:
Step-by-step explanation:
To solve the question we refresh our knowledge of the quotient rule.
For a function f(x) express as a ratio of another functions u(x) and v(x) i.e
, the derivative is express as
from 
we assign u(x)=lnx and v(x)=x^2
and the derivatives
.
Note the expression used in determining the derivative of the logarithm function.it was obtain from the general expression of logarithm derivative i.e 
If we substitute values into the quotient expression we arrive at
If Bryan wants to make $2000 dollars then he needs to solve this equation:
2000=500+150x
-500 -500
1500=150x divide by 150 on both sides
x=10
10 cars
Logx (8x-3) - logx 4 = 2
logx [(8x-3)/4] = 2
x^2=(8x-3)/4
4x^2=4(8x-3)/4
4x^2=8x-3
4x^2-8x+3=8x-3-8x+3
4x^2-8x+3=0
4(4x^2-8x+3=0)
(4^2)(x^2)-8(4x)+12=0
(4x)^2-8(4x)+12=0
(4x-2)(4x-6)=0
2(4x/2-2/2)2(4x/2-6/2)=0
4(2x-1)(2x-3)=0
4(2x-1)(2x-3)/4=0/4
(2x-1)(2x-3)=0
Two options:
1) 2x-1=0
2x-1+1=0+1
2x=1
2x/2=1/2
x=1/2
2) 2x-3=0
2x-3+3=0+3
2x=3
2x/2=3/2
x=3/2
Answer: Two solutions: x=1/2 and x=3/2
Answer:
m∠FEH = 44°
m∠EHG = 64°
Step-by-step explanation:
1) The given information are;
The angle of arc m∠FEH = 272°, the measured angle of ∠EFG = 116°
Given that m∠FEH = 272°, therefore, arc ∠HGF = 360 - 272 = 88°
Therefore, angle subtended by arc ∠HGF at the center = 88°
The angle subtended by arc ∠HGF at the circumference = m∠FEH
∴ m∠FEH = 88°/2 = 44° (Angle subtended at the center = 2×angle subtended at the circumference)
m∠FEH = 44°
2) Similarly, m∠HGF is subtended by arc m FEH, therefore, m∠HGF = (arc m FEH)/2 = 272°/2 = 136°
The sum of angles in a quadrilateral = 360°
Therefore;
m∠FEH + m∠HGF + m∠EFG + m∠EHG = 360° (The sum of angles in a quadrilateral EFGH)
m∠EHG = 360° - (m∠FEH + m∠HGF + m∠EFG) = 360 - (44 + 136 + 116) = 64°
m∠EHG = 64°.
