The most stable conformation of 3-isopropyl-1,1dimethylcyclohexane equatorial ethyl group (more stable). The stability of ethylcyclohexane's equatorial conformer exceeds that of its axial conformer by 7.4 kJ/mol.
According to the previous section, the chair conformation with the equatorial methyl group is more stable because it reduces steric repulsion, and as a result, the equilibrium favors the more stable conformer. Strongly favoring the equatorial shape is methylcyclohexane. The methyl group is in close proximity to the axial hydrogens in the axial conformation, which has an energetically unfavorable effect known as a 1,3-diaxial interaction. The methyl group prefers the equatorial shape as a result. The conformation of ethylcyclohexane in which the ethyl group is in the equatorial position is the most stable.
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Answer:
yeild solid iron
Explanation:
When two solutions of ionic compounds are mixed, a solid may form. This type of reaction is called a precipitation reaction, and the solid produced in the reaction is known as the precipitate.
Answer:
Before the equivalence point, conductivity is decreasing. After the equivalence point, conductivity is increasing
Explanation:
In solution H2SO3 produce H+ ions and SO3²⁻ ions. In the same way, NaOH produce Na⁺ and OH⁻ ions. The conductivity of a solution is directly proportional to the concentration of ions in a solution. During titration, you are adding more NaOH (That is, more Na⁺ and OH⁻ ions). But each moles of OH⁻ reacts with H⁺ ion producing H₂O. That means the moles of Na⁺ that you are adding = Moles of H⁺ are been consumed. The concentration of ions remains approximately constant. But, H⁺ ion conducts better than Na⁺ ion. That means before the equivalence point, conductivity is decreasing. But after the equivalence point you will add OH- ions in excess increasing ion concentration increasing the conductivity:
After equivalence point, conductivity is increasing.
Answer:
It provides the electrons that "make" electricity and it contains the electrons that are involved in molecular bond formation.
Answer:
c
O2: 7 mol
CO2: 4 mil
