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3 years ago

Which variables can affect the speed of a chemical reaction? (Choose all that apply)

Chemistry

1 answer:

Leya [2.2K]3 years ago

7 0

Your answer is B(I'm not very much sure about this one), C, and D.

I hope very much that I am correct, hope this helps you.

~Onyx~

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Temperature is _____ to the average kinetic energy of a gas.

d1i1m1o1n [39]

Answer: Option (b) is the correct answer.

Explanation:

As on increasing the temperature, the molecules gain more kinetic energy due to which they tend to collide and move rapidly from one place to another.

Thus, we can conclude that when temperature is increased, the kinetic energy of the molecules increases.

This means that temperature is directly proportional to the average kinetic energy of a gas.

8 0

2 years ago

Read 2 more answers

Potassium permanganate as a symbol

Alexxx [7]

Answer: KMnO4-

Explanation:

You're looking at one potassium plus a polyatomic ion.

So K plus MnO4, equals:

KMnO4-

It also has a molar mass of 158.04 g/mol, I don't know if you need that, but I thought it would be nice to include it.

7 0

3 years ago

If we react 5.4g of sodium chloride with an unknown amount of fluorine gas, we produce 4.9g of sodium fluoride and 3.7g chlorine

Bumek [7]

Answer:

4.43 g

Explanation:

The reaction between sodium chloride and flourine gas is given as;

NaCl + F2 --> NaF + Cl2

From the stochiometry of the equation;

1 mol of NaCl reacts eith 1 mol of F2 to form 1 mol of NaF and Cl2

Mass of 1 mol of F2 = 38g

Mass of 1 mol of sodium flouride, NaF = 42g

This means 38g of flourine reacted with NaCl to form 42g of NaF

xg of F2 would form 4.9g of NaF

38 = 42

x = 4.9

x = 4.9 * 38 / 42

x = 4.43 g

4 0

2 years ago

Nitrogen trioxide ionic covalent or both

lesya692 [45]

Answer:

that's all I can do

your welcome

8 0

3 years ago

Predict the products of La(s) + O2(aq) ->

mina [271]

Answer:

i. La (s) + O2 (g) => LaO2 (s)

ii. La (s) + O2 (g) => La2O (s)

III. La (s) + O2 (g) => La2O3 (s)

Explanation:

Hello there!

When you are given such a problem for completing the chemical equations, what you have to understand is that metals are found in groups I, II and III. While Oxygen is a group VI element.

From the above question I have considered that my La(s), solid is either Sodium (Na) - group I, Magnesium - group II and Aluminum - group III.

In a reaction, there is exchange of electrons given by their oxidation numbers (I, II and III - for our metals above)

The chemical equations are thus;

i. Na (s) + O2 (g) => NaO (s)

ii. Mg (s) + O2 (g) => Mg2O (s)

iii. Al (s) + O2 (g) => Al2O3 (s)

Relate this to the problem and it will be;

i. La (s) + O2 (g) => LaO2 (s)

ii. La (s) + O2 (g) => La2O (s)

III. La (s) + O2 (g) => La2O3 (s)

I hope this helps you to understand better. Enjoy your studies

3 0

2 years ago