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sasho [114]
4 years ago
11

Iron (Fe) reacts with copper sulfate (CuSO4) to form iron (II) sulfate. In this reaction, Cu2+ gains electrons to form Cu. Which

statement is true about this reaction?
Fe(s) + CuSO4(aq) → FeSO4(aq) + Cu(s)

A.) Cu undergoes decomposition.

B.) Cu undergoes oxidation.

C.) Cu undergoes reduction.

D.) Cu undergoes combustion.
Chemistry
2 answers:
Y_Kistochka [10]4 years ago
6 0

C.  Cu undergoes reduction.

Anna11 [10]4 years ago
4 0

Answer: C.) Cu undergoes reduction.

Explanation:

Fe(s)+CuSO_4(aq)\rightarrow FeSO_4(aq)+Cu(s)

I)  Oxidation reaction : involves loss of electrons and there is an increase in oxidation state number.

Fe\rightarrow Fe^{2+}+2e^-

Fe metal has undergone oxidation, as its oxidation state is changing from 0 to +2 in FeSO_4.

ii) Reduction reaction : involves gain of electrons and there is a decrease in oxidation state number.

Cu^{2+}+2e^-\rightarrow Cu

Copper(II) ion has undergone reduction, as its oxidation state is changing from 2+ to 0. Copper ions are getting converted into copper metal.

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Answer:

A. Yes

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Explanation:

A. Yes

B. Determination of the new temperature of the gas.

Let the initial pressure be P

From the question given above, the following data were obtained.

Initial pressure (P1) = P

Initial temperature (T1) = 19 °C

Final pressure (P2) = ⅓ P1 = ⅓P = P/3

Final temperature (T2) =?

Next, we shall convert 19 °C to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

Initial temperature (T1) = 19 °C

Initial temperature (T1) = 19 °C + 273

Initial temperature (T1) = 292 K

Since the volume is constant, we can obtain the new temperature of the gas as illustrated below:

Initial pressure (P1) = P

Initial temperature (T1) = 292 K

Final pressure (P2) = P/3

Final temperature (T2) =?

P1/T1 = P2/T2

P/292 = P/3 /T2

P/292 = P/3T2

Cross multiply

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Divide both side by P

3T2 = (292 × P)/P

3T2 = 292

Divide both side by 3

T2 = 292/3

T2 = 97.33 ≈ 97 K

Finally, we shall convert 97 K to celcius temperature. This can be obtained as follow:

T(°C) = T(K) – 273

T(K) = 97

T(°C) = 97 – 273

T(°C) = –176 °C

Thus, the new temperature of the gas is –176 °C.

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