What are the domain and range of the function on the graph?

Please be kind and help me on this question.<br> WARNING: only if your good at math thank you

AVprozaik [17]

Short Answer: The first three are absolutely true. Congruency is maintained if all you are doing is shifting the figure 8 spaces away. Since the figures are congruent, their corresponding parts are equal and the statements made are always true. That's the guiding principle.

A is true. See the short answer.

B is True. You have gone 8 units away. The distance between the old G and the new one is 8 units. This is not a congruency property but it is true because it is given. You haven't altered the shape or rotatated it.

C is true by conguency. You have just shifted things 8 units. You have maintained equality and you have maintained distance between corresponding parts.

That leaves D. If the figures are regular, that will be true. If they are not regular, non corresponding external angles cannot be guaranteed to be true.

7 0

3 years ago

If h(x) = 48, find x

babymother [125]

Answer: 0523 i think this the answer i don't know

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Is x^(-2)+5 a polynomial expression? Why or why not?

Lynna [10]

Answer:

it is not because a polynomial cannot have a negative power

3 0

3 years ago

Julio walks 1/5 miles in 3/2 hours how far does he walk in one hours

nevsk [136]

3 1/2 ÷ 1 1/4
7/2 ÷ 5/4
7/2 · 4/5
28/10
2.8

Julio walks 2.8 miles in one hour.

4 0

2 years ago

Read 2 more answers

A membership committee of three is formed from four eligible members. Let the eligible members be represented by A, B, C, and D.

yKpoI14uk [10]

The correct statement is:

There are four ways to choose the committee.
There are three ways to form the committee if person D must be on it.
If persons B and C must be on the committee, there are two ways to form the committee.

It is given that:

A membership committee of three is formed from four eligible members.

1) There are four ways to choose the committee.

This statement is true.

Since we have to choose 3 members out of the 4 members so we can use the method of combination.

2) There are three ways to form the committee if person D must be on it.

This statement is also true.

Since D has to be in the committee, this means we have to choose 2 more people out of the three people to form the committee.

3) If seven members are eligible next year, then there will be fewer combinations.

This statement is wrong.

Since we have to choose 3 members out of 7 members so the number of possible combinations will be:

There are 35 combinations possible.

4) If persons B and C must be on the committee, there are two ways to form the committee.

If B and C have to be in the committee then we have to choose just one person out of the two people left.

Hence, the statement is true.

5) If persons A and C must be on the committee, then there is only one way to form the committee.

If A and C have to be on the committee then as in the last option we have to choose any one of the two-person left.

So possible number of ways is 2.

Hence, the statement is false.

Learn more about committee here: brainly.com/question/425830

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<em>Your question is incomplete. Please read below to find the missing content.</em>

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A membership committee of three is formed from four eligible members. Let the eligible members be represented by A, B, C, and D. The possible outcomes include S = {ABC, ABD, ACD, BCD}.

Which statements about the situation are true? Check all that apply.

There are four ways to choose the committee.

There are three ways to form the committee if person D must be on it.

If seven members are eligible next year, then there will be fewer combinations.

If persons B and C must be on the committee, there are two ways to form the committee.

If persons A and C must be on the committee, then there is only one way to form the committee.

8 0

2 years ago