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3 years ago

14

1 the probability of rolling a number greater than 5 on a standard number cube.

1 answer:

Allushta [10]3 years ago

4 0

Answer: 1/6

Step-by-step explanation:

Because there's only one number that's greater than 5 on a numbered cube and that's '6'

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Help please!!!! I’ll appreciate it so much!

bazaltina [42]

Answer:

13. x = 4

14. x = -16

15. x = 11

Step-by-step explanation:

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3 years ago

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Help please!!!<br> What is P(0.6 ≤ z ≤ 2.12)?<br> 16% <br> 26% <br> 73% <br> 98%

Lelu [443]

26% is the answer to your question

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3 years ago

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1 and 2 are a linear pair, and 2 and 3 are vertical angles. m 2=(5+4 y) and m 3=(6 y-25). what is m 1

poizon [28]

Vertical angles are equal to each other:
    ∠2    =    ∠3
   5 + 4y = 6y - 25
→ 30 = 2y
→    15 = y

∠2 = 5 + 4y = 5 + 4(15) = 5 + 60 = 65

linear pairs equal 180:
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→ ∠1 + 65 = 180
→ ∠1 = 115

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3 years ago

The answer to this problem?

LenaWriter [7]

The simplified expression of $\sqrt{\frac{162x^9}{2x^{27}}}$ is $\frac{9}{x^9}$

<h3>How to simplify the expression?</h3>

The expression is given as:

$\sqrt{\frac{162x^9}{2x^{27}}}$

Divide 162 and 2 by 2

$\sqrt{\frac{81x^9}{x^{27}}}$

Take the square root of 81

$9\sqrt{\frac{x^9}{x^{27}}}$

Apply the quotient rule of indices

$9\sqrt{\frac{1}{x^{27-9}}}$

Evaluate the difference

$9\sqrt{\frac{1}{x^{18}}}$

Take the square root of x^18

$\frac{9}{x^9}$

Hence, the simplified expression of $\sqrt{\frac{162x^9}{2x^{27}}}$ is $\frac{9}{x^9}$

Read more about expressions at:

brainly.com/question/723406

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2 years ago

How many repeating digits are in 0.536

creativ13 [48]

There are 3 repeating digits in 0.536 because there are 3 numbers behind the decimal

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3 years ago

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