A 600-MW steam power plant, which is cooled by a nearby river, has a thermal efficiency of 56 percent. Determine the rate of hea
1 answer:
Answer:
471.43MW
Explanation:
the rate of heat transfer to the power plant is determined from the thermal efficiency equation
Qh =
Qh = 600 MW / 0.56
Qh =1071.43MW
The rate of heat transfer to the river is determined from the first law related to heat engine
QL = Qh - Wout
= 1071.43 - 600
= 471.43MW
the heat will be lost to the surrounding air as it passes through pipes and other surrounding components
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Answer:
The temperature T= 648.07k
Explanation:
T1=input temperature of the first heat engine =1400k
T=output temperature of the first heat engine and input temperature of the second heat engine= unknown
T3=output temperature of the second heat engine=300k
but carnot efficiency of heat engine =
where Th =temperature at which the heat enters the engine
Tl is the temperature of the environment
since both engines have the same thermal capacities <em> </em> therefore
We have now that
multiplying through by T
multiplying through by 300
-
The temperature T= 648.07k