Answer:
diameter is 14 mm
Explanation:
given data
power = 15 kW
rotation N = 1750 rpm
factor of safety = 3
to find out
minimum diameter
solution
we will apply here power formula to find T that is
power = 2π×N×T / 60 .................1
put here value
15 ×
= 2π×1750×T / 60
so
T = 81.84 Nm
and
torsion = T / Z ..........2
here Z is section modulus i.e = πd³/ 16
so from equation 2
torsion = 81.84 / πd³/ 16
so torsion = 416.75 / / d³ .................3
so from shear stress theory
torsion = σy / factor of safety
so here σy = 530 for 1020 steel
so
torsion = σy / factor of safety
416.75 / d³ = 530 × 
/ 3
so d = 0.0133 m
so diameter is 14 mm
Answer:
0.34
Explanation:
See the attached picture.
Answer:
The answer is 960 kg
Explanation:
Solution
Given that:
Assume the initial dye concentration as A₀
We write the expression for the dye concentration for one hour as follows:
ln (C₁) = ln (A₀) -kt
Here
C₁ = is the concentration at 1 hour
t =time
Now
Substitute 480 g for C₁ and 1 hour for t
ln (480) = ln (A₀) -k(1) ------- (1)
6.173786 = ln (A₀) -k
Now
We write the expression for the dye concentration for three hours as follows:
ln (C₃) = ln (A₀) -k
Here
C₃ = is the concentration at 3 hour
t =time
Thus
Substitute 480 g for C₃ and 3 hour for t
ln (120) = ln (A₀) -k(3) ------- (2)
4.787492 = ln (A₀) -3k
Solve for the equation 1 and 2
k =0.693
Now
Calculate the amount of blue present initially using the expression:
Substitute 0.693 for k in equation (2)
4.787492 = ln (A₀) -3 (0.693)
ln (A₀) =6.866492
A₀ =e^6.866492
= 960 kg
Therefore, the amount of the blue dye present from the beginning is 960 kg
Answer:
10.984mm
Explanation:
by elastic modulus
stress=modulus of elasticity*strain
stress=loading/area area" cross-section"
11mm=0.011m
area=π(d/2)^2=π(0.011/2)^2=9.503*10^-5 square meter
stress=55000/(9.503*10^-5)=578.745 MPa
convert MPa and GPa to pascal.
strain=stress/modulus=(578.745*10^6)/(125*10^9)=0.00463............axial strain
v=Poisson ratio
lateral strain=(-v)*axial strain= -0.31*0.00463
lateral strain= -1.4353*10^-3=change in diameter/ original diameter
change in diameter=(-1.4353*10^-3)*0.011= -1.57883*10^-5 m
negative indicates decrease in diameter.
decrease in dia.=0.01578mm
new diameter=11-0.01578= 10.984mm
Answer:
At the end of the vowel, the soft palate (is lowered) so that the air flows out the (nasal passage). At the same time, the BACK of the tongue rises to articulate with the VELUM, preventing air from escaping through the MOUTH. The lips remain OPEN. The vocal folds continue to SOUND.
Explanation:
This is the way in which sound is produced in any language through the use of our organs of speech called articulators.
NOTE:
This question should be in English Category not Engineering. I believe that was an oversight from your end.
