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AlexFokin [52]
3 years ago
15

If the open circuit voltage of a circuit containing ideal sources and resistors is measured at 6 V, while the current through th

e short circuit across the circuit is 200 mA, what would be the power absorbed by an ideal current source, I_s= 100 mA, placed across the terminals?
Engineering
1 answer:
Trava [24]3 years ago
7 0

Given Information:

Current of Ideal source = Is = 100 mA = 0.100 A

Open circuit voltage = Voc = 6 V

Short circuit current = Isc = 200 mA = 0.200 A

Required Information:

Power absorbed by idea current source = ?

Answer:

Power absorbed by idea current source = 0.3 Watts

Explanation:

Ideal Current Source:

An ideal current source doesn't have internal resistance and provides constant current regardless of the voltage supplied to the circuit.

The power absorbed by the ideal source can be found using

P = Is²R

Where Is is the ideal source current and R can be found using

R = Voc/Isc

Where Voc is the open circuit voltage and Isc is the short circuit current.

R = 6/0.200

R = 30 Ω

Therefore, the power absorbed by the ideal current source is

P = Is²R

P = (0.100)²*30

P = 0.3 Watts

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1) Find the time in seconds to reach full charge in an RL circuit with L = 5 H and R = 100 ohms
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Explanation:

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by using the formula,

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8 0
3 years ago
Provide an argument justifying the following claim: The average (as defined here) of two Java ints i and j is representable as a
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<em>I hope this information can help you.</em>

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