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Ilya [14]
3 years ago
7

Which of the following factors affects the amount of heat absorbed by a substance?

Chemistry
1 answer:
Ilia_Sergeevich [38]3 years ago
3 0

Answer:

\boxed{\text{Specific heat capacity of the substance}}

Explanation:

The formula for the amount of heat absorbed by a substance is

q = mCΔT

Thus, the three factors are the

  • mass
  • specific heat capacity
  • temperature change

The only factor that is on your list is

\boxed{\textbf{Specific heat capacity of the substance}}

The shape of the substance has no effect, nor do its melting and boiling points.

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3 years ago
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Determine if these molecules and ion are polar.
Colt1911 [192]

Answer:

a. Polar

b. Polar

c. Non-polar

d. Non-polar

Explanation:

a. H_3O^+, hydronium cation contains a positive charge. Just as any other ion, it is polar, as it has a net charge.

b. H_2S has the same shape as water. There are two lone pairs on sulfur atom which produce an overall dipole moment in this molecule, the bent structure is polar.

c. PCl_5 is non-polar, as the central atom, phosphorus, doesn't contain any lone pairs, all the dipole moments cancel out: two dipole moments in the vertical plane, P-Cl, and three P-Cl dipoles in the horizontal plane within a trigonal bipyramidal shape.

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3 0
3 years ago
112 g of aluminum carbide react with 174 g water to produce methane and aluminum hydroxide in the reaction shown below.
dolphi86 [110]

<u>Answer:</u> 4.999 moles of excess reactant will be left over.

<u>Explanation:</u>

Limiting reagent is defined as the reagent which is completely consumed in the reaction and limits the formation of the product.

Excess reagent is defined as the reagent which is left behind after the completion of the reaction.

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}       .....(1)

Given mass of aluminium carbide = 112 g

Molar mass of aluminium carbide = 143.96 g/mol

Putting values in equation 1:

\text{Moles of aluminium carbide}=\frac{112g}{143.96g/mol}=0.778mol

For the given chemical reaction:

2Al_4C_3(s)+12H_2O(l)\rightarrow 3CH_4(g)+4Al(OH)_3(s)

By the stoichiometry of the reaction:

2 moles of aluminium carbide reacts with 12 moles of water

So, 0.778 moles of aluminium carbide will react with = \frac{12}{2}\times 0.778=4.668 mol of water

Given mass of water = 174 g

Molar mass of water = 18 g/mol

Putting values in equation 1:

\text{Moles of water}=\frac{174g}{18g/mol}=9.667mol

Moles of excess reactant (water) left = 9.667 - 4.668 = 4.999 moles

Hence, 4.999 moles of excess reactant will be left over.

8 0
2 years ago
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prohojiy [21]
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What is the volume of 70.0 g of ether if the density of ether is 0.70 g/mL?
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M=70.0 g
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