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sasho [114]
3 years ago
6

Convert 25 gigaseconds into centiseconds​

Chemistry
1 answer:
dangina [55]3 years ago
6 0

25 gigaseconds is equal to 2,500,000,000,000 centiseconds

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An oxygen atom, with 6 electrons (of a possible 8) in its outer electron shell, has the capacity to form a maximum of how many c
Ksenya-84 [330]
Oxygen can form two covalent bonds, 
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3 years ago
Suppose that a TLC plate is spotted with samples 1.0 cm above the bottom of the plate. Select the consequence of inserting the p
Oksi-84 [34.3K]

Answer:

The compounds in the samples will leach into the pool of developing solvent resulting in poor resolution.

Explanation:

The aim of thin layer chromatography is the separation of a mixture. Usually, the stationary phase is spotted with the mixture. A mark is made with a pencil at the point to be spotted.

It is necessary to note that the solvent must be below the spot where the mixture is. This is because, if the solvent is above the spot of the mixture to be separated, the components of the mixture will dissolve away in the solvent resolution in poor separation. This is exactly what will happen when the sample is spotted at 1.0 cm above the bottom when the solvent is 1.2 cm above the bottom.

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3 years ago
The combined gas law states that
seropon [69]

Answer:

Option B. PV = nRT.

Explanation:

From the above,

C = PV / T. (1)

But, C is directly proportional to n, where R is the gas constant i.e

C & n

C = nR

Substituting the value of C into equation (1), we have:

C = PV / T

nR = PV / T

Cross multiply to express in linear form

nRT = PV

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8 0
2 years ago
2.0g divided by 34.0 g times 100% equals what?
Lubov Fominskaja [6]

Answer: \frac{1}{17}

Explanation: \frac{2}{34}\cdot \:100\%\:=\frac{1}{17}

I tried my best, I hope this helps!

7 0
3 years ago
What is the molality of a solution that contains 1.34 moles of NaCl in 2.47 kg of solvent
dsp73

The molality is 0.54 M when 1.34 moles of NaCl is present in 2.47 kg of solvent.

<u>Explanation:</u>

Molality is the measure of how much of amount of solute is dissolved in the solvent. So it is calculated as the ratio of moles of solute to the grams of solvent.

         \text {Molality}=\frac{\text {Moles of solute}}{\text {Mass of solvent}}

As in this case, the solute is NaCl and solvent is unknown. So the moles of solute is given as 1.34 moles and the mass of solvent is given as 2.47 kg.

Hence, \text { molality }=\frac{1.34}{2.47}= 0.54 \mathrm{M}

Thus, the molality is 0.54 M when 1.34 moles of NaCl is present in 2.47 kg of solvent.

8 0
3 years ago
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