The mass of CO2 obtained in the reaction by stoichiometry is 30.8 g.
The equation of the reaction is;
2HCl(aq) + CaCO3(s) -----> CaCl2(aq) + H2O(l) + CO2(g)
The mass of the HCl reacted is obtained from;
Density = mass/volume
Mass = Density × volume = 1.140 g/mL × 43.435 mL = 49.5 g
Number of moles of HCl = 49.5 g/36.5 g/mol = 1.4 moles
If 2 moles of HCl reacts produces 1 mole of CO2
1.4 moles of HCl produces x moles of CO2
x = 1.4 moles × 1 mole/ 2 moles = 0.7 moles
Mass of CO2 produced = 0.7 moles x 44 g/mol = 30.8 g
In the second case, the same volume of acid is used hence the same mass of CO2 is obtained.
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