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pashok25 [27]
2 years ago
13

Tums is a popular remedy for acid indigestion. A typical Tums tablet contains calcium carbonate mixed with inert substances. Whe

n ingested, it reacts with stomach acids (hydrochloric acid) to produce carbon dioxide gas. When a 1.241 g tablet reacted with 43.435 mL of hydrochloric acid, carbon dioxide gas was produced and the final solution weighed 52.122 g. Calculate the number of liters of carbon dioxide gas released. When a 1.241g Tums tablet reacted with 43.435 mL of hydrochloric acid (density: 1.140 g/mL), carbon dioxide gas was produced and the resulting solution weighed 50.571 g. Calculate the mass of carbon dioxide gas released.
Chemistry
1 answer:
barxatty [35]2 years ago
3 0

The mass of CO2 obtained in the reaction by stoichiometry is 30.8 g.

The equation of the reaction is;

2HCl(aq) + CaCO3(s) -----> CaCl2(aq) + H2O(l) + CO2(g)

The mass of the HCl reacted is obtained from;

Density = mass/volume

Mass = Density × volume =  1.140 g/mL ×  43.435 mL = 49.5 g

Number of moles of HCl =  49.5 g/36.5 g/mol = 1.4 moles

If 2 moles of HCl reacts produces 1 mole of CO2

1.4 moles of HCl produces x moles of CO2

x = 1.4 moles × 1 mole/ 2 moles = 0.7 moles

Mass of CO2 produced = 0.7 moles  x 44 g/mol = 30.8 g

In the second case, the same volume of acid is used hence the same mass of CO2 is obtained.

Learn more about stoichiometry: brainly.com/question/9743981

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Question number 10 & 11, answer please and thank you
nika2105 [10]

Answer:

molarity = moles of solution/liters of solution

molarity = 1 mole/2 liters

molarity = 0.5 M

molarity = 50 moles/200 kg

molarity = 0.25 M

Explanation:

3 0
3 years ago
How do particles of gas create pressure
Fantom [35]

Answer:

Gas pressure is caused when the gas particles hit the walls of their container. The more often the particles hit the walls, and the faster they are moving when they do this, the higher the pressure. This is why the pressure in a tyre or balloon goes up when more air is pumped in

Explanation:

5 0
3 years ago
If the mass percentage composition of a compound is 72.1% Mn and 27.9% O, its empirical formula is
mojhsa [17]

Answer:

MnO- Manganese Oxide

Explanation:

Empirical formula: This is the formula that shows the ratio of elements

present in a  

compound.

   

How to determine Empirical formula

1. First arrange the symbols of the elements present in the compound

alphabetically to  determine the real empirical formula. Although, there

are exceptions to this rule, E.g H2So4

2. Divide the percentage composition by the mass number.

3. Then divide through by the smallest number.

4. The resulting answer is the ratio attached to the elements present in

a compound.

           

                                                                              Mn                         O    

                         

% composition                                                      72.1                      27.9    

                       

Divide by mass number                                       54.94                     16  

                                 

                                                                               1.31                      1.74    

                       

Divide by the smallest number                         1.31                      1.31                          

                                                                               1                    1.3

                                                 

The resulting ratio is 1:1

 

Hence the Empirical formula is MnO, Manganese oxide

8 0
3 years ago
Consider the synthesis of ammonia 3 H2+ N2 à 2 NH3 If a student were to react 38.5 g of nitrogen gas, how many moles of ammonia
Wittaler [7]

Answer:

2.75 mol

Explanation:

Given data:

Mass of Nitrogen = 38.5 g

Moles of ammonia produced = ?

Solution:

Chemical  equation:

N₂ + 3H₂    →     2NH₃

Number of moles of nitrogen:

Number of moles = mass/ molar mass

Number of moles = 38.5 g/ 28 g/mol

Number of moles = 1.375 mol

Now we will compare the moles of ammonia and nitrogen from balance chemical equation.

           N₂            :            NH₃

            1              :             2

           1.375       :           2×1.375 = 2.75 mol

Thus 2.75 moles of ammonia  are produced from 38.5 g of nitrogen.

4 0
3 years ago
What is that the theoretical yield of aluminum oxide I if 3.20 mol of aluminum metal is exposed to 2.70 mole of oxygen
photoshop1234 [79]

Answer:

163.2g

Explanation:

First let us generate a balanced equation for the reaction. This is shown below:

4Al + 3O2 —> 2Al2O3

From the question given, were were told that 3.2moles of aluminium was exposed to 2.7moles of oxygen. Judging by this, oxygen is excess.

From the equation,

4moles of Al produced 2moles of Al2O3.

Therefore, 3.2moles of Al will produce = (3.2x2)/4 = 1.6mol of Al2O3.

Now, let us covert 1.6mol of Al2O3 to obtain the theoretical yield. This is illustrated below:

Mole of Al2O3 = 1.6mole

Molar Mass of Al2O3 = (27x2) + (16x3) = 54 + 48 =102g/mol

Mass of Al2O3 =?

Number of mole = Mass /Molar Mass

Mass = number of mole x molar Mass

Mass of Al2O3 = 1.6 x 102 = 163.2g

Therefore the theoretical of Al2O3 is 163.2g

8 0
3 years ago
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