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pashok25 [27]
2 years ago
13

Tums is a popular remedy for acid indigestion. A typical Tums tablet contains calcium carbonate mixed with inert substances. Whe

n ingested, it reacts with stomach acids (hydrochloric acid) to produce carbon dioxide gas. When a 1.241 g tablet reacted with 43.435 mL of hydrochloric acid, carbon dioxide gas was produced and the final solution weighed 52.122 g. Calculate the number of liters of carbon dioxide gas released. When a 1.241g Tums tablet reacted with 43.435 mL of hydrochloric acid (density: 1.140 g/mL), carbon dioxide gas was produced and the resulting solution weighed 50.571 g. Calculate the mass of carbon dioxide gas released.
Chemistry
1 answer:
barxatty [35]2 years ago
3 0

The mass of CO2 obtained in the reaction by stoichiometry is 30.8 g.

The equation of the reaction is;

2HCl(aq) + CaCO3(s) -----> CaCl2(aq) + H2O(l) + CO2(g)

The mass of the HCl reacted is obtained from;

Density = mass/volume

Mass = Density × volume =  1.140 g/mL ×  43.435 mL = 49.5 g

Number of moles of HCl =  49.5 g/36.5 g/mol = 1.4 moles

If 2 moles of HCl reacts produces 1 mole of CO2

1.4 moles of HCl produces x moles of CO2

x = 1.4 moles × 1 mole/ 2 moles = 0.7 moles

Mass of CO2 produced = 0.7 moles  x 44 g/mol = 30.8 g

In the second case, the same volume of acid is used hence the same mass of CO2 is obtained.

Learn more about stoichiometry: brainly.com/question/9743981

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Please Help Me!!!
sergejj [24]

Answer:

The products are carbon dioxide and water

Explanation:

Step 1: Data given

Combustion = a reaction in which a substance reacts with oxygen gas, releasing energy in the form of light and heat. Combustion reactions must involve  O2  as one reactant.

Step 2: The complete combustion of C3H7OH:

For the combustion of 1-propanol, we need O2.

The products of this combustion are CO2 and H2O.

C3H7OH + O2→ CO2 + H2O

On the left side we have 3x C (in c3H7OH), on the right side we have 1x C (in CO2). To balance the amount of C, we have to multiply CO2 on the right side by 3

C3H7OH + O2→ 3CO2 + H2O

On the left side we have 8x H (in C3H7OH) and 2x on the right side (in H2O). To balance the amount of H, we have to multiply H2O, on the right side by 4.

C3H7OH + O2→ 3CO2 + 4H2O

On the left side we have 3x O (1x in C3H7OH and 2x in O2), on the right side we have 10x O (6x in CO2 and 4x in H2O).

To balance the amount of O on both sides, we have to multiply C3H7OH by 2, multiply O2 by 9. Then we have to multiply 3CO2 by 2 and 4H2O by 2. Now the equation is balanced.

2C3H7OH + 9O2→ 6CO2 + 8H2O

For 2 moles propanol, we need 9 moles of O2 to produce 6 moles of CO2 and 8 moles Of H2O

The products are carbon dioxide and water

7 0
3 years ago
Bill's recipe for onion soup calls for 4.0 lb of thinly sliced onions . if an onion has an average mass of 115 g , how many onio
Pavlova-9 [17]

Answer:

A lot

Explanation:

BillBill's recipe for onion soup calls for 4.0 lb of thinly sliced onions . if an onion has an average mass of 115 g , how many onions does Bill need ?

7 0
2 years ago
What is the relationship between chemical equilibrium and the rates of forward and reverse reaction?
Nataly_w [17]

Answer:

c

Explanation:

the rate of a forward process must be exactly balanced by the rate of the reverse process.

3 0
3 years ago
Read 2 more answers
mixture of N 2 And H2 Gases weighs 13.22 g and occupies a volume of 24.62 L at 300 K and 1.00 atm.Calculate the mass percent of
anygoal [31]

<u>Answer:</u> The mass percent of nitrogen gas and hydrogen gas is 91.41 % and 8.59 % respectively.

<u>Explanation:</u>

To calculate the number of moles, we use the equation given by ideal gas equation:

PV = nRT

where,

P = Pressure of the gaseous mixture = 1.00 atm

V = Volume of the gaseous mixture = 24.62 L

n = number of moles of the gaseous mixture = ?

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = Temperature of the gaseous mixture = 300 K

Putting values in above equation, we get:

1.00atm\times 24.62L=n_{mix}\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 300K\\\\n_{mix}=\frac{1.00\times 24.62}{0.0821\times 300}=0.9996mol

We are given:

Total mass of the mixture = 13.22 grams

Let the mass of nitrogen gas be 'x' grams and that of hydrogen gas be '(13.22 - x)' grams

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

<u>For nitrogen gas:</u>

Molar mass of nitrogen gas = 28 g/mol

\text{Moles of nitrogen gas}=\frac{x}{28}mol

<u>For hydrogen gas:</u>

Molar mass of hydrogen gas = 2 g/mol

\text{Moles of hydrogen gas}=\frac{(13.22-x)}{2}mol

Equating the moles of the individual gases to the moles of mixture:

0.9996=\frac{x}{28}+\frac{(13.22-x)}{2}\\\\x=12.084g

To calculate the mass percentage of substance in mixture we use the equation:

\text{Mass percent of substance}=\frac{\text{Mass of substance}}{\text{Mass of mixture}}\times 100

Mass of the mixture = 13.22 g

  • <u>For nitrogen gas:</u>

Mass of nitrogen gas = x = 12.084 g

Putting values in above equation, we get:

\text{Mass percent of nitrogen gas}=\frac{12.084g}{13.22g}\times 100=91.41\%

  • <u>For hydrogen gas:</u>

Mass of hydrogen gas = (13.22 - x) = (13.22 - 12.084) g = 1.136 g

Putting values in above equation, we get:

\text{Mass percent of hydrogen gas}=\frac{1.136g}{13.22g}\times 100=8.59\%

Hence, the mass percent of nitrogen gas and hydrogen gas is 91.41 % and 8.59 % respectively.

5 0
3 years ago
A 25.0 mL sample of an acetic acid solution is titrated with a 0.175 M NaOH solution. The equivalence point is reached when 26.6
joja [24]

<u>Answer:</u> The concentration of CH_3COOH comes out to be 0.16 M.

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is CH_3COOH

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=1\\M_1=?M\\V_1=25mL\\n_2=1\\M_2=0.175M\\V_2=26.6mL

Putting values in above equation, we get:

1\times M_1\times 25=1\times 0.175\times 26.6\\\\M_1=0.1862M

Hence, the concentration of CH_3COOH comes out to be 0.1862 M.

4 0
2 years ago
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