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Levart [38]
2 years ago
9

Convert 3841 cL to L. SHOW WORK PLS

Chemistry
1 answer:
barxatty [35]2 years ago
4 0

Answer:

1 cl = 1 * 10-5 m³

1 L = 1 * 10-3 m³

1 L = 0.001 m³

1 m³ = (1/0.001) L

1 m³ = 1000 L

1 cl = 1 * 10-5 * 1000 L

1 cl = 0.01 L

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What mass of CCl4 is required to prepare a 0.25 m solution using 115 g of hexane? (molar mass of ccl4 = 153.81 g/mol and molar m
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4.42 g mass of CCl4 is required to prepare a 0.25 m solution using 115 g of hexane.

It's easy to find the molecular mass of a compound with these steps: Determine the molecular formula of the molecule. Use the periodic table to determine the atomic mass of each element in the molecule. Multiply each element's atomic mass by the number of atoms of that element in the molecule.

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