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frutty [35]
3 years ago
10

When 2 Forces Act in the SAME DIRECTION they are _____.

Physics
1 answer:
posledela3 years ago
7 0

Explanation:

they are balance force

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While following the directions on a treasure map a pirate walks 37.0 m north and then turns and walks 8.5 m east what is the mag
kogti [31]

Answer: 38\ m

Explanation:

For this exercise you can use the Pythagorean theorem to find the magnitude of the resultant displacement.

Then:

d^2=\triangle x^2+\triangle y^2

You can observe that the square of the displacement is equal to the sum of the square  of the horizontal displacement and the square of the vertical displacement.

Since the pirate walks 37.0 meters north and then turns and walks 8.5 meters east:

\triangle x=37.0\ m\\\triangle y=8.5\ m

Substituting values and solving for "d", you get:

d=\sqrt{(37.0\ m)^2+(8.5\ m)^2}\\\\d=38\ m

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3 years ago
A pizza parlor is considering adding taco pizza and Hawaiian pizza to its
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Answer: 79

Explanation:

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3 years ago
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A +8.75 μC point charge is glued down on a horizontal frictionless table. It is tied to a -6.50 μC point charge by a light, nonc
lisov135 [29]

(a) The tension on the wire when the two charges have opposite signs is 383.5 N.

(b) The tension on the wire if both charges were negative is 3.640.25 N.

The given parameters;

  • <em>first charge, q₁ = 8.75 μC </em>
  • <em>second charge, q₂ = -6.5 μC  </em>
  • <em>electric field, E = 1.85 x 10⁸ N/C</em>
  • <em>distance between the two charges, r = 2.5 cm</em>

<em />

(a)

The attractive force between the charges is calculated as follows;

F_1 = \frac{kq_1q_2}{r^2} \\\\F_1 = \frac{(9\times 10^9) \times (8.75\times 10^{-6})\times (-6.5\times 10^{-6})}{(0.025)^2} \\\\F_1 = -819 \ N

The force on the negative charge due to the electric field is calculated as follows;

F_2 = Eq_2\\\\F_2 = (1.85 \times 10^8) \times (6.5 \times 10^{-6})\\\\F_2 = 1202.5 \ N

The tension on the wire is the resultant of the two forces and it is calculated as follows;

T = F_2 + F_1\\\\T = 1202.5 - 819\\\\T = 383.5 \ N

(b) when the two charges are negative

The repulsive force between the two charges is calculated as follows;

F_1 = \frac{kq_1q_2}{r^2} \\\\F_1 = \frac{(9\times 10^9) \times (-8.75\times 10^{-6})\times (-6.5\times 10^{-6})}{(0.025)^2} \\\\F_1 = 819 \ N

The force on the first negative charge due to the electric field is calculated as follows;

F_2 = Eq_1\\\\F_2 = (1.85 \times 10^8)\times (8.75 \times 10^{-6})\\\\F_2 = 1618.75 \ N

The force on the second negative charge due to the electric field is calculated as follows;

F_3 = Eq_2\\\\F_3 = (1.85 \times 10^8) \times (6.5 \times 10^{-6})\\\\F_3 = 1202.5 \ N

The tension on the wire is the resultant of the three forces and it is calculated as follows;

T= F_1 + F_2 + F_3\\\\T= 819 + 1618.75 + 1202.5\\\\T = 3,640.25 \ N

Learn more here:brainly.com/question/19565286

5 0
3 years ago
How does the entropy of steam compare to the entropy of ice?
Dmitriy789 [7]

The answer is; The entropy of steam is larger than because it is more disordered than ice

Entropy is synonymous to the degree of disorder or randomness of molecules in a system. The molecules of steam are far apart from each other and move randomly in the system colliding with each other. Those of ice has less kinetic energy, vibrate more or less in a fixed position in the structiure, and are arranged in a orderd fashion


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a cinder block is sitting on a platform 20 m high. it weighs 7.9 the block has potential energy. calculate it.
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I assume that 7.9 is 7.9 newton .I think the answer is the correct answer

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